What is the solution to the system of equations? Use any method you like, but be sure to show all work.
1 answer:
These are known as simultaneous equations,, 2x + y= -3 take this as 1st equation x-2y=-4 take this as 2 nd equation therefore x - 2y= -2 should be multiplied by 2 inorder to cut off 2x and 2x from the first and second equations. by multiplying we get 2x - 4y = -4 therefore 3rd equation should be substracted from 1st equation... now, 2x -4y - 2x -y = -4-(-3) therefore, -2x and +2x is cut. as a result -5y= -1 therefore y = 1 /5 then let us find x 2x + y = -3 ::: 2x + 1/5= -3 therefore 2x= -3-1/5 finally, x= -16/5÷2 then x= 8/5
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If so, start by factoring the numerator. Then cancel any common term in the numerator and denominator. If you end up with no denominator, then use the original denominator. Set it equal to zero and solve for x. That value of x will be the restriction.