All categories

3 years ago

Approaching deadline help is highly appreciated thanks in advance

Mathematics

1 answer:

givi [52]3 years ago

7 0

Check the picture below, notice the repeats on the x-coordinates, there are more, that just happen to be one.

You might be interested in

-20 2 -6 -18 4 -4 put them from least to greatest

dedylja [7]

-20 -18 -6 -4 2 4 this is the answer

6 0

2 years ago

Read 2 more answers

A single card is drawn from a 52 standard deck. Find the conditional probability that the card is a heart given that it's a jack

MakcuM [25]

You can use the formula for conditional probability as Puzzling did. However in this problem it is easier just to restrict yourself and enumerate the cases that are left.

There are 4 jacks. One of them is a heart. So the probability is 1/4. 

If you want to look at what the formula for conditional probability does, it adjusts your probability by restricting the "universe". 

P(heart and jack)/P(jack) 
= (1/52)/(4/52) = 1/4

7 0

2 years ago

which description best describes the solution to the following system of equations y= -2x +3 y= -x + 1

marin [14]

For this case we have the following system of equations:
$y = -2x +3

y = -x + 1$
Equating the values of y we have:
$-2x +3 = -x + 1
$
From here, we can clear the value of x.
We have then:
$-2x + x = 1 - 3

-x = -2

x = 2$
Then, we look for the value of y.
For this, we substitute x in any of the equations:
$y = -x + 1

y = -2 + 1

y = -1$
Answer:
The ordered pair solution of the system of equations, is given by:
$(x, y) = (2, -1)$

3 0

2 years ago

Read 2 more answers

(Easy 30 points) Solve the equation to find a positive value of c: 3^2 + 4^ = c^2

shusha [124]

Answer:

C= 5, -5

Step-by-step explanation:

8 0

3 years ago

Please Help! This is a trigonometry question.

liraira [26]

$\large\begin{array}{l} \textsf{From the picture, we get}\\\\ \mathsf{tan\,\theta=\dfrac{2}{3}}\\\\ \mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{2}{3}}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\qquad\mathsf{(i)} \end{array}$

$\large\begin{array}{l} \textsf{Square both sides of \mathsf{(i)} above:}\\\\ \mathsf{(3\,sin\,\theta)^2=(2\,cos\,\theta)^2}\\\\ \mathsf{9\,sin^2\,\theta=4\,cos^2\,\theta}\qquad\quad\textsf{(but }\mathsf{cos^2\theta=1-sin^2\,\theta}\textsf{)}\\\\ \mathsf{9\,sin^2\,\theta=4\cdot (1-sin^2\,\theta)}\\\\ \mathsf{9\,sin^2\,\theta=4-4\,sin^2\,\theta}\\\\ \mathsf{9\,sin^2\,\theta+4\,sin^2\,\theta=4} \end{array}$

$\large\begin{array}{l} \mathsf{13\,sin^2\,\theta=4}\\\\ \mathsf{sin^2\,\theta=\dfrac{4}{13}}\\\\ \mathsf{sin\,\theta=\sqrt{\dfrac{4}{13}}}\\\\ \textsf{(we must take the positive square root, because }\theta \textsf{ is an}\\\textsf{acute angle, so its sine is positive)}\\\\ \mathsf{sin\,\theta=\dfrac{2}{\sqrt{13}}} \end{array}$

________

$\large\begin{array}{l} \textsf{From (i), we find the value of }\mathsf{cos\,\theta:}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{2}\,sin\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\diagup\!\!\!\! 2}\cdot \dfrac{\diagup\!\!\!\! 2}{\sqrt{13}}}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\sqrt{13}}}\\\\ \end{array}$

________

$\large\begin{array}{l} \textsf{Since sine and cosecant functions are reciprocal, we have}\\\\ \mathsf{sin\,2\theta\cdot csc\,2\theta=1}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{sin\,2\theta}\qquad\quad\textsf{(but }}\mathsf{sin\,2\theta=2\,sin\,\theta\,cos\,\theta}\textsf{)}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\,sin\,\theta\,cos\,\theta}}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\cdot \frac{2}{\sqrt{13}}\cdot \frac{3}{\sqrt{13}}}} \end{array}$

$\large\begin{array}{l} \mathsf{csc\,2\theta=\dfrac{~~~~1~~~~}{\frac{2\cdot 2\cdot 3}{(\sqrt{13})^2}}}\\\\ \mathsf{csc\,2\theta=\dfrac{~~1~~}{\frac{12}{13}}}\\\\ \boxed{\begin{array}{c}\mathsf{csc\,2\theta=\dfrac{13}{12}} \end{array}}\qquad\checkmark \end{array}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2150237

$\large\textsf{I hope it helps.}$

Tags: trigonometry trig function cosecant csc double angle identity geometry

8 0

3 years ago