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Elanso [62]
3 years ago
15

Kari, juan, tami and brad are the first 4 people in line. Kari is not first in line. Tami had at least two people ahead of her i

n line. Juan is third. Give the order of the first four people
Mathematics
1 answer:
Liula [17]3 years ago
6 0
So, Juan is 3rd, and Tami has at least 2 ppl in front of her, she can't be third because Juan is, so she's fourth. Kari is not 1st, leaving the only space to be 2nd from Kari.
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Which graph represents exponential decay? On a coordinate plane, a straight line has a negative slope. On a coordinate plane, a
RoseWind [281]

Answer:

The correct option is (C).

Step-by-step explanation:

The exponential function representing decay is as follows:

y=y_{0}\cdot e^{kt};\ k

Here,

<em>y</em> = final value  

<em>y</em>₀ = initial value  

<em>k</em> = growth rate  

<em>t</em> = time passed

The graph represents exponential decay is:

"On a coordinate plane, a graph approaches y = 0 in quadrant 1 and curves up into quadrant 2."

Thus, the correct option is (C).

3 0
3 years ago
Read 2 more answers
Maria is draining her hot tub at a rate of 5.5 gallons per minute. Is the amount of water left in the pool a function of the amo
AleksandrR [38]

The amount of water in the pool after t minutes is modeled by the linear function V(t) = V(0) - 5t, hence it is a function of time.

A <em>linear function</em> for the amount of water in the pool, considering that it is <u>drained at a rate of a gallons per minute</u>, is modeled by:

V(t) = V(0) - at

  • In which V(0) is the initial volume.

In this problem, draining her hot tub at a rate of <u>5.5 gallons per minute</u>, hence a = 5.5, and:

V(t) = V(0) = 5.5t

Which is a function of time.

To learn more about linear functions, you can take a look at brainly.com/question/13488309

8 0
2 years ago
The right expression to calculate how much money will be in an investment account 14 years from now if you deposit $5,000 now an
Svet_ta [14]

Answer:

The expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].

Step-by-step explanation:

The formula to compute the future value is:

FV=PV[1+\frac{r}{100}]^{n}

PV = Present value

r = interest rate

n = number of periods.

It is provided that $5,000 were deposited now and $3,000 deposited after 6 years at 10% compound interest. The amount of time the money is invested for is 14 years.

The expression to compute the amount in the investment account after 14 years is,

FV=5000[1+\frac{10}{100}]^{14}+3000[1+\frac{10}{100}]^{14-6}\\FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}

The future value is:

FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}\\=18987.50+6430.77\\=25418.27

Thus, the expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].

4 0
3 years ago
Explain in your own words what happens when a car's tires are changed from the original size to a LARGER size. How is the odomet
Nadusha1986 [10]

Answer:

Step-by-step explanatin

it affects it because your going from smaller tires witch make it easier to make turns go faster things like that when you put bigger tires on the car it is gonna raise the car and have a whole differnt outlook

6 0
3 years ago
Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
3 years ago
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