Use the power, product, and chain rules:

• product rule

• power rule for the first term, and power/chain rules for the second term:

• power rule

Now simplify.

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.
On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

Differentiate both sides and you end up with the same derivative:

Answer:
$681.60
Step-by-step explanation:
<u><em>Given:</em></u>
<em>During a sale, a store offered a 20% discount on a TV that originally sold for $710. After the sale, the discounted price of the TV was marked up by 20%</em>
<u><em>To Find:</em></u>
<em>What was the price of the TV after the markup? Round to the nearest cent.</em>
<u><em>Solution:</em></u>
$710 × (1 + 20%) × (1 - 20%)
$710 × 1.2 × (1-0.2)
$710 × 1.2 × 0.8
($710 × 1.2) × 0.8
852 × 0.8
= $681.60
<u><em>Kavinsky</em></u>
$360.00*.28= 100.80
<span>Or do a portion </span>
<span>28%/100%=100.8/x </span>
<span>Then cross multiply </span>
<span>10080=28x </span>
<span>x=360</span>
The answer is b: 95.03 ft^2
Divide 5.5 by 2 to get the radius of 2.75.
Use 4(pi)(r)^2 to get the surface area of the sphere.
Answer:
y=-50x-20
Step-by-step explanation: