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3 years ago

ABC is isosceles with AB=AC=8 units and BC=6 units. D and E are midpoints of AB and BC respectively. what is the length of DE

Mathematics

1 answer:

Andrew [12]3 years ago

4 0

The length between point d&e is <u>3 units</u> long

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a courier earns a fixed amount for each package she delivers, and yesterday her average hourly wage was $12.50 an hour. if she w

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She makes 6.25$ for each package

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4 years ago

chris has 5 stack of dvd each stack has10 dvds if chris add 2 more identical stacks of dvds to the shelves how many dvds will ch

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4 years ago

Find the product. (a2)(2a3)(a2 – 8a + 9) 2a7 – 16a6 + 18a5 2a7 – 16a6 – 18a5 2a8 – 16a7 + 18a6 2a12 – 16a7 + 18a6

Alexandra [31]

Answer:

2 $a^{7}$ - 16 $a^{6}$ + 18 $a^{5}$

Step-by-step explanation:

Given

(a²)(2a³)(a² - 8a + 9) ← multiply the first 2 factors

= 2 $a^{5}$ (a² - 8a + 9) ← distribute the parenthesis by 2 $a^{5}$

= 2 $a^{7}$ - 16 $a^{6}$ + 18 $a^{5}$

3 0

3 years ago

Read 2 more answers

write an equation in slope intercept form for the line that passes through the points (3,2) and(-9,6)

netineya [11]

Answer:

y = - $\frac{1}{3}$ x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 2) and (x₂, y₂ ) = (- 9, 6)

m = $\frac{6-2}{-9-3}$ = $\frac{4}{-12}$ = - $\frac{1}{3}$ , hence

y = - $\frac{1}{3}$ x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 9, 6), then

6 = 3 + c ⇒ c = 6 - 3 = 3

y = - $\frac{1}{3}$ x + 3 ← in slope- intercept form

4 0

3 years ago

Sonja plays tennis and started a tournament with 43 aces on the season. The graph relates her total season aces with the number

Pani-rosa [81]

<h2>Answer</h2>

$-6x+y=43$

<h2>Explanation</h2>

The first thing we need to do is find the slope of our line. To do it we are using the slope formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

where

$m$ is the slope of the line

$(x_{1},y_{1})$ are the coordinates of the first point on the line

$(x_{2},y_{2})$ are the coordinates of the second point

From our graph we can get the points (0, 43) and (2, 55), so $x_{1}=0$ , $y_{1}=43$ , $x_{2}=2$ , and $y_{2}=55$ . Let's replace the values in our slope formula:

$m=\frac{55-43}{2}$

$m=\frac{12}{2}$

$m=6$

Now that we have our slope, we can use the point-slope formula:

$y-y_{1}=m(x-x_{1})$

$y-43=6(x-0)$

$y-43=6x$

But remember that the equation of a line in standard form is $Ax+Ay=C$ , so we need to subtract $6x$ and add 43 to both sides of our point slope equation:

$y-43=6x$

$-6x+y-43+43=6x-6x+43$

$-6x+y=43$

We can conclude that the equation in standard form that represent the relationship in the graph is $-6x+y=43$ .

3 0

3 years ago