All categories

2 years ago

Find the product and simplify your answer. 7a5(-3a4+5a-5)

Mathematics

1 answer:

Alex Ar [27]2 years ago

3 0

$\text{Hey there!}$

$\mathsf{Use\ distributive\ property\ to\ solve}}\\\\\text{The formula is : a(b + c)=a(b)+a(c)=b+ac}\\\\\mathsf{7a^5(-3a^4+5a-5)}\\\\\mathsf{7a^5(-3a^4)=-21a^9}\\\\\mathsf{7a^5(5a)=3a^6}\\\\\mathsf{7a^5(-5)=-35a^5}$

$\boxed{\boxed{\mathsf{Your\ answer: \boxed{\mathsf{-21a^9+35a^6-35a^5}}}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

You might be interested in

I need help please?!!!!

Marianna [84]

The answer is the last option: The associative property of multiplication

6 0

2 years ago

What is the equation for a parabola with a focus of (0,-4) and a directrix of y=4 if the vertex is at the origin?..1)..y=1/16x2.

OlgaM077 [116]

Answer:

y = - $\frac{1}{16}$ x²

Step-by-step explanation:

Since the vertex is at the origin and the focus at (0, - 4) then the parabola opens vertically down with equation

x² = 4py ( p is the distance from the vertex to the focus )

Here p = - 4 ( focus is below the vertex ), thus

x² = 4(- 4)y = - 16y ( divide both sides by - 16 )

y = - $\frac{1}{16}$ x²

3 0

2 years ago

.<br> Which of the following graphs represents the quadratic function f(x)=(x-3)^2+5?

dedylja [7]

Answer:

The graph below show how this equation's graph looks like!

3 0

3 years ago

Read 2 more answers

An international polling agency estimates that 36 percent of adults from Country X were first married between the ages of 18 and

alukav5142 [94]

Answer:

(B) 0.2843

Step-by-step explanation:

Let d be the difference in proportions from Country X and Country Y who were first married between the ages of 18 and 32.

Then hypotheses are

$H_{0}$ : d=0.15

$H_{a}$ : d<0.15

Test statistic can be found using the equation

$z=\frac{p1-p2-0.15}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of Country X (0.36)

p2 is the sample proportion of Country Y (0.26)

p is the pool proportion of p1 and p2 ( $\frac{60*0.36+50*0.26}{50+60}=0.31$ )

n1 is the sample size of adults from Country X (60)

n2 is the sample size of adults from Country Y (50)

Then $z=\frac{0.36-0.26-0.15}{\sqrt{{0.31*0.69*(\frac{1}{60} +\frac{1}{50}) }}}$ ≈ 0.5646

p-value of test statistic is ≈ 0.2843

p-value states the probability that the difference in proportions between a random sample of 60 adults from Country X and a random sample of 50 adults from Country Y who were first married between the ages of 18 and 32 is at least 0.15

3 0

2 years ago

A new, simple test has been developed to detect a particular type of cancer. The test must be evaluated before it is used. A med

g100num [7]

Answer:

0.3333 = 33.33% probability of a randomly chosen person not having cancer given that the test indicates cancer

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$