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antoniya [11.8K]
4 years ago
5

Describe this number line and the numbers and fractions shown.

Mathematics
2 answers:
Mariana [72]4 years ago
6 0

Answer:

The number line goes from negative two to two.

The numbers shown by the number line (-2, -1, 0, 1 and 2) are all integers.

Between each pair of numbers, there are 4 equal segments, each one of 1/4 = 0.25 units length. Therefore we can locate, for example, 1.25, 0.5 and -0.75 at the number line.

maria [59]4 years ago
6 0

Answer:

The number line shows numbers -2 through 2.

The number line is divided into fourths.

Zero is at the center of the number line.

Numbers get larger as you move to the right on the number line.

Numbers get smaller as you move to the left on the number line.

Step-by-step explanation:

just answered on edge 2020

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There are 90 fith-grade students going on a feild trip. Each student gives the teacher $9.25 to cover admission to the theater a
garri49 [273]

Answer:

they each get $5.75 for lunch

Step-by-step explanation:

9.25 x 90 students = 832.50

832.50 -315 = 517.50

517.50 / 90 = 5.75

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3 years ago
Solve the Exponential Equation.<br><br> 5 to the power of x equals 3125
pashok25 [27]

Answer:

x = 5

Step-by-step explanation:

5 times 5 = 25

25 times 5 = 125

125 times 5 = 625

625 times 5 = 3125

There are five fives.

x = 5

6 0
3 years ago
Read 2 more answers
Solve the following system using the elimination method: 2x-4y=2 -4x+6y=-4
Tomtit [17]

Answer:

(1, 0)

Step-by-step explanation:

Given the 2 equations

2x - 4y = 2 → (1)

- 4x + 6y = - 4 → (2)

Multiplying (1) by 2 and adding to (2) will eliminate the x- term

4x - 8y = 4 → (3)

Add (2) and (3) term by term

(- 4x + 4x) + (6y - 8y) = (- 4 + 4), simplifying gives

- 2y = 0 ⇒ y = 0

Substitute y = 0 in (1) or (2)

Substituting in (1) gives

2x - 0 = 2, that is

2x = 2 ( divide both sides by 2 )

x = 1

Solution is (1, 0 )

3 0
3 years ago
Dawn does the sum 34 + 12 = 46 in a maths lesson.
Naily [24]
46-12=34 is the correct answer
5 0
3 years ago
A pole that is 2.6 m tall casts a shadow that is 1.03 m long. At the same time, a nearby tower casts a shadow that is 46.25 m lo
photoshop1234 [79]

Answer:

Therefore the height of the tower is 116.75 m.

Step-by-step explanation:

Given that a pole that is 2.6 m tall casts a shadow that is 1.03 m long.

Here the height of a object directly proportional to the shadow. It means

Height of the object ∝ shadow

Height of the object= k.shadow

[k is the proportional constant.]

\Rightarrow \frac{h}{s} =k    [Height of object is denoted by h and shadow is denoted by s]

Then,

\frac{h_1}{s_1} =k       [h₁ is the height of the pole and s₁is the length of the shadow]

Again for the tower

\frac{h_2}{s_2}=k      [h₂ is the height of the tower and s₂ is the length of the shadow]

Therefore,

\frac{h_1}{s_1}=\frac{h_2}{s_2} =k

\Rightarrow\frac{h_1}{s_1}=\frac{h_2}{s_2}............(1)

Given h_1 = 2.6 m  ,s_1=1.03m  and   s_2=46.25m

Putting the value of h_1,s_1 and s_2  equation (1)

\frac{2.6}{1.03}=\frac{h_2}{46.25}

\Rightarrow h_2 \times1.03= 2.6\times 46.25          [cross multiplication]

\Rightarrow h_2 = \frac{2.6\times 46.25}{1.03}

\Rightarrow h_2= 116.75

Therefore the height of the tower is 116.75 m.

3 0
3 years ago
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