Step by Step :
1. 9(2j + 7 + 5j)
2. (9)(2j) + (9)(7) + (9)(5j)
3. 18j + 63 + 45j
Answer: 63j + 63
Answer: A. 136
B. 8.3
C. 155
D. 27.3
Step-by-step explanation:
Gdhssse bheee
Answer:
f(x) = 26500 * (0.925)^x
It will take 7 years
Step-by-step explanation:
A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. Then use your formula to determine when the value of the car will be $15,000 to the nearest year.
To find the formula we will use this formula: f(x) = a * b^x. A is our initial value which in this case is $26500. B is how much the value is increasing or decreasing. In this case it is decreasing by 7.5% per year. Since the car value is decreasing we will subtract 0.075 from 1. This will result in the formula being f(x) = 26500 * (0.925)^x. Now to find the value of the car to the nearest year of when the car will be 15000 we plug 15000 into f(x). 15000 = 26500 * (0.925)^x. First we divide both side by 26500 which will make the equation: 0.56603773584=(0.925)^x. Then we will root 0.56603773584 by 0.925. This will result in x being 7.29968 which is approximately 7 years.
-9y-42x
Because they are like terms that is the lowest they can go
Answer:
D
Step-by-step explanation:
10*20=200
200 + 1020= 1220
Works for the first one
20*20=400
400+ 1020=1420
Works for the second one
30*20=600
600+1020=1620
Works for the third one, and all the others one so forth.
You take the number on the left (10, 20, 30, 40, 50, 60, 70) and times it by 20, replacing the x in the equation with the number on the left side of the table. Then you add the number from said equation to result of the multiplication from the first step.
