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Amanda [17]
3 years ago
11

3x + 1 = 8 I need the steps and answer.

Mathematics
2 answers:
Marat540 [252]3 years ago
8 0

3x + 1 = 8

move +1 to the other side

sign changes from +1 to -1

3x+1-1= 8-1

3x= 7-1

divide by 3 for both sides to get x by itself

3x/3= 7/3

Answer:

x= 7/3 and x= 2 1/3

ICE Princess25 [194]3 years ago
7 0

Answer:

\large\boxed{x=\dfrac{7}{3}=2\dfrac{1}{3}}

Step-by-step explanation:

3x+1=8\qquad\text{subtract 1 from both sides}\\\\3x+1-1=8-1\\\\3x=7\qquad\text{divide both sides by 3}\\\\\dfrac{3x}{3}=\dfrac{7}{3}\\\\x=\dfrac{7}{3}

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A shopkeeper allows 10% discount on the marked price of a bicycle. If a costomer pays Rs 4068 with 13% VAT find the marked price
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\large{ \tt{❁ \: S \: O \: L \: U \: T \: I \: O \: N \: ❁}}

  • We're provided - Discount % = 10 % , Cost with VAT [ SP with VAT ] = Rs 4068 & VAT % = 13%. We're asked to find out the marked price of the bicycle. Let's start :

\large{ \tt{❇ \: FIND \: SP \: WITHOUT \: VAT \: / \: SP\: ❇}}

\large{ \tt{❃ \: SP  \: with \: VAT= SP + VAT\% \: of \: SP}}

\large{ \tt{⇢ \: 4068 = SP + 13\% \: of \: SP}}

\large{ \tt{⇢ \: 4068 = SP +  \frac{13}{100}  \: sp}}

\large{ \tt{⇢ \: 4068 =  \frac{100 \:  \: SP + 13 \: SP}{100} }}

\large{ \tt{⇢ \: 4068 =  \frac{113 \: SP}{100} }}

\large{ \tt{⇢ \: 113 \: SP = 406800}}

\large{ \tt{⇢ \: SP =  \frac{406800}{113} }}

\large{ \tt{⇢ \: SP = 3600}}

  • Hence , SP = Rs 3600

\large{ \tt{✽ \: NOW , \: FIND \: THE \: MP \:✽ }}

  • Let Marked Price [ MP ] be x.

\large {\tt{❃ \: SP = MP - dis\% \: of \: MP}}

\large{ \tt{⇾ \: 3600 = x - 10\% \: of \: x}}

\large{ \tt{⇾ \: 3600 = x -  \frac{10}{100} } \: x}

\large{ \tt{⇾ \: 3600 =  \frac{100x - 10x}{100} }}

\large{ \tt{⇾ \: 3600 =  \frac{90x}{100} }}

\large{ \tt{⇾ \: 90x = 360000}}

\large{ \tt{⇾ \: x =  \frac{360000}{90} }}

\large{ \tt{⇾ \: x = Rs \: 4000}}

\large{ \boxed{ \boxed{ \tt{☂ \: OUR \: FINAL \: ANSWER :  \boxed {\tt {\: Rs \: 4000}}}}}}

  • Hope I helped! Let me know if you have any questions regarding my answer and don't hesitate to reach out to me if you need any assistance! :)
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