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AnnZ [28]
3 years ago
10

3. The upward velocity of the water in a particular fountain is given in feet per second by

Mathematics
1 answer:
zzz [600]3 years ago
6 0

ll,,Step-by-step explanation:

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Joanne's Dress Shop received an invoice dated July 25 for $1,400, with terms of 2/10, 1/15, n/60. On August 8, Joanne's Dress Sh
ss7ja [257]

The actual amount that should be credited is $757.58.

<u>Solution:</u>

Given that,

2% Discount if paid in 10 days.

1% Discount if paid in 15 days, (but greater that 10 days)

Net due in 60 days.

That is,

\bold{1400\times0.98 = 1372} will close the acount on days 1-10

\bold{1400\times0.99 = 1386} will close the acount on days 11-15

And August 8 is Day 15 and falls under the 1% discount rule.

Therefore, we have to divide the partial payment by the complement of the discount rate.

\bold{\Rightarrow\frac{750}{0.99} = 757.58} from the balance, and \bold{1400.00 - 757.58 = 642.42} is due by day 60.

5 0
4 years ago
If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the
Gnesinka [82]

Answer:

C

Step-by-step explanation:

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18,

x=(m+9)/2

y=(2m+15)/2

z=(3m+18)/2

the average of x, y, and z

=(x+y+z)/3

=(m+9+2m+15+3m+18)/3

=(6m+42)/3

=2m+14

ans is C

8 0
3 years ago
Read 2 more answers
Someone give me an easy algebra problem thx ​
likoan [24]

Answer:

write the equation of the line that passes through (7,6) and (-1,2) in a slope intercept form.

7 0
3 years ago
Mishka is on a long road trip, and she averages 75 mph for 2 hours while she's driving on the highway. While she's driving on si
slega [8]

If she goes 75 mph for 2 hours, that's 150 miles altogether. 45 mph for 1 hour is 45 miles, so 150 + 45 is 195 miles.

8 0
4 years ago
In five consecutive tosses of a coin, what is the probability of not getting a tail until the 5th coin toss?
jasenka [17]
The proabability would be 50% always
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3 years ago
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