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skelet666 [1.2K]
3 years ago
9

PLEASE ANSWER QUICKLY!!!

Mathematics
1 answer:
AveGali [126]3 years ago
8 0

You just need to know the terms so it should be B- Associative property of Multiplication

<em>I hope this helps, love!</em>

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Write the terms a 1a1​, a 2a2​, a 3a3​, and a 4a4 of the following sequence. If the sequence appears to​ converge, make a conjec
Arturiano [62]

Answer:

Step-by-step explanation:

WE are given that a_n = \frac{(-1)^{n+1}}{5n-4}. Then, to now the first for terms, we must replace n by 1,2,3,4 respectively. Then

a_1 = \frac{(-1)^2}{5(1)-4} = \frac{1}{1}= 1

a_2 = \frac{(-1)^3}{5(2)-4} = \frac{-1}{6}

a_3 = \frac{(-1)^4}{5(3)-4} = \frac{1}{11}= 1

a_4 = \frac{(-1)^5}{5(4)-4} = \frac{-1}{16}= 1

Note that as n increase, a_n gets closer to 0. So, the limit of this sequence is 0.

6 0
3 years ago
If tn = 4n+1, find t1, t2, t3, and tn+1. Express tn+1−tn in its simplest form.
Doss [256]

Answer:

t_1=5

t_2=9

t_3=13

t_{n+1}-t_n=4

Step-by-step explanation:

We have that:

t_n=4n+1

When we substitute n=1, we get:

t_1=4*1+1=5

When we substitute n=2 we get:

t_2=4*2+1=9

When we substitute n=3, we get:

t_3=4*3+1=13

When we substitute n=n+1, we get:

t_{n+1}=4*(n+1)+1=4n+5

Now

t_{n+1}-t_n=4n+5-(4n+1)

We expand and simplify to obtain:

t_{n+1}-t_n=4n+5-4n-1

t_{n+1}-t_n=4

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3 years ago
How many zeros are in the standard form of six hundred thousand, twenty? Explain
creativ13 [48]
Standard form is the literal standard form you write numbers in, so it would be 600,020. Hope this helps!
3 0
2 years ago
3\sqrt{-27x^6y^9} ????????
ivann1987 [24]

Answer: 9x^3 y^4 sqrt -3y

7 0
3 years ago
the graph of liner function f passes through the point (1,-9) ad has a slope of -3 what is the zero of f
Lostsunrise [7]

Answer:

answer 4 im pretty sure

Step-by-step explanation:

i did da math

8 0
2 years ago
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