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3 years ago

If the cos of angle A = 1/2, then find the measure of angle A.

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

5 0

Answer:

<A= 60 degrees

Step-by-step explanation:

Since cosA=0.5, we can take the inverse cos of 0.5 to get 60 degrees.

Hope this helped!

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2:3= 10: 12:15 = 4: 1:5= 5: 15:30 = 1 :

I am Lyosha [343]

Answer:

I think this is the answer

Step-by-step explanation:

2:3=10:15

12:15=4:5

1:5=5:25

15:30=1:2

5 0

3 years ago

I have 300 beads.My sister has 60 more beads than I do.How many beads do we have altogether

Vesnalui [34]

660 beads

I have 300

My sister has 360

300+ 360= 660

8 0

3 years ago

Mai and Tyler work on the equation 2/5b+1=-11 together. Mais soulution is b=-25 and Tyler’s is b=-28. Here is their work. Do you

Anika [276]

Answer:

No I don't agree with their solution; both their answers are wrong.

Correct answer is $b=-30$ .

Step-by-step explanation:

Given:

$\frac{2}{5}b+1=-11$

Now given:

According to Mai $b = -25$ and According to Tyler $b = -28$

Now we need to find which of them is correct.

So we will solve the given equation we get;

$\frac{2}{5}b+1=-11$

Subtracting both side by 1 we get;

$\frac{2}{5}b+1-1=-11-1\\\\\frac{2}{5}b =-12$

Now Multiplying both side $\frac{5}{2}$ we get;

$\frac{2}{5}b\times\frac{5}{2}= -12 \times \frac{5}{2}\\\\b=-6\times 5\\\\b=-30$

Hence both of them are incorrect, correct answer is $b=-30$ .

3 0

3 years ago

Will give brainlest

Vilka [71]

Answer:

B. 1 5/6

Step-by-step explanation:

$\frac{5}{6}*2\frac{1}{5} = 1\frac{5}{6}$

5 0

3 years ago

Read 2 more answers

A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0

3 years ago