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3 years ago

How can using equivalent ratios help you operate a business?

1 answer:

4 0

Hi there

Using equivalent ratios to help operate a business is useful for financial ratios.
There are common size ratios, liquidity ratios, efficiency ratios, and solvency ratios.

Ratios are used to let us compare one item to another. (For example, comparing 1 teacher to 25 students, or 1:25)

Did you have any answers to chose from? I just figured I'd provide you with what I knew about this subject to help in case there were no options to chose from.

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A swimsuit is in sale for 45.50. if the sales price is discounted 5%from the orginal price. what was the original price. round t

AnnyKZ [126]

The answer is 42.80 , 2.28 is what they saved and i got the .80 cents because i rounded up from .78

8 0

3 years ago

Complete the number sentence to make it true 54.609____54.69

lidiya [134]

Answer:

54.609 < 54.69

Step-by-step explanation:

54.69 is closer to a whole number than 54.609 making it the greater number

3 0

3 years ago

According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann

mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable Y is defined as the number of consecutive time intervals in which the water supply remains below a critical value y₀.

The random variable Y follows a Geometric distribution with parameter p = 0.409.

The probability mass function of a Geometric distribution is:

$P(Y=y)=(1-p)^{y}p;\ y=0,12...$

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

$P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844$

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

$=(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780$

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable Y as follows:

$\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445$

Compute the standard deviation of the random variable Y as follows:

$\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88$

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

= P (Y ≥ 3.325)

= P (Y ≥ 3)

= 1 - P (Y < 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2)

$=1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064$

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0

3 years ago

E^x = 25 ...................

anzhelika [568]

X is equal to about 3.218876

5 0

3 years ago

Read 2 more answers

X + 5y = -27 -2x - 5y = 24

Rashid [163]

Answer:

Step-by-step explanation:

x+5y=-27

-2x-5y=24

If the signs are the same u minus if they are different u add

So they are different were gonna add

x+5y=-27

-2x-5y=24

-1=-3

You cant divide it further x=-3

Next were gonna subsitute in any equation

x(-3)+5y=-27

-3+5y=-27

+3 to -27

-7+3=-24

5y=24

24/5=4.8 y=4.8

I hope this helps.

4 0

3 years ago