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mihalych1998 [28]
3 years ago
7

Kyle is constructing a bar graph to display the percentage of students enrolled in AP courses from 1996-2005. He is planning to

create a bar graph with a scale in 5% increments. Is this an appropriate choice given the data? Why or why not? A) No, he should construct a pie chart instead. B) No, he should construct a line graph instead. C) No, he should use a scale with larger increments such as 0, 10, and 20. D) No, because his percentages are so close together it will be difficult to determine differences in the years if he uses a scale of 5% increments. He should use a smaller scale such as 1% increments.
Mathematics
1 answer:
svetoff [14.1K]3 years ago
4 0
The answer to the question is C.
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I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

\text { Volume of a cylinder }=\pi r^{2} h

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e  

\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}

<em><u>Ratio for the volumes of two cylinders</u></em>

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}

Cancelling the common terms, we get

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)

Substituting we get,

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}

Hence, the ratio of volume of two cylinders is 8 : 27

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