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3 years ago

What isfour hundred eight thousand. Seventeen in expanded form

Mathematics

2 answers:

saul85 [17]3 years ago

7 0

The answer to the question is 40000+8000+10+7

BartSMP [9]3 years ago

4 0

400000+8000+10+7 is the answer

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Y = – 3

KonstantinChe [14]

The best approximation for the solution to this system of equations is (-2.2,-3)

Option C is correct.

Step-by-step explanation:

Solving the system of equations to get the exact value of x:

$y = -3\\y = x-0.8$

Let

$y = -3\,\,eq(1)\\y = x-0.8\,\,eq(2)$

Putting value of y from eq(1) into eq(2)

$-3=x-0.8$

$x=-3+0.8$

$x=-2.2$

So, Value of x is -2.2

The best approximation for the solution to this system of equations is:

x=-2.2 and y = -3

(-2.2,-3)

Option C is correct.

Keywords: System of equations

Learn more about system of equations at:

#learnwithBrainly

6 0

3 years ago

Read 2 more answers

How to solve these numbers I forgot

Anastasy [175]

40 because 3+6+12 = 21 and 8+11+21 =40

7 0

3 years ago

A taxi service charges a $10 flat fee plus $3 per mile traveled. If an equation is made to calculate the total cost of a taxi ri

sertanlavr [38]

Flat rate=y intercept
rate per mile=slope
y=3x+10 would be it

1.
3 is the value of the slope (3 dollars per mile)

2.
y intercept is (0,10)

3.
22 miles
y=3(22)+10
y=66+10
y=76
$76

8 0

3 years ago

amir lent Rs. 600 to hameed for 2 years and Rs. 150 to aman for 4 year and received altogether from both Rs. 90 as simple intere

aniked [119]

Interest = Pin = principal * interest rate * number of years

Let interest rate be i, then
600*i*2+150*i*4=90
1200i+600i = 90
i=90/(1200+600)=90/1800=1/20=0.05 or 5%

8 0

2 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

2 years ago