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3 years ago

Can u please help me with 27

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

5 0

The answer would be 237.375. To get this answer, you will first use the formula given for each unit. First, you will do the first unit by putting 8 to the third power, or basically 8x8x8. After you get the product 512, you will then do the next unit. Do that one by doing 6.5 to the third power, or as followed, 6.5x6.5x6.5. Once you get the product 274.625, you will then subtract that from 512. You will then receive the answer 237.375.

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4 years ago

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5=1/5w in algebraically

Rudik [331]

Answer:w = -5/4

Step-by-step explanation:

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4 years ago

Which equation represents a line that passes through (4,1/3) and has a slope of 3/4?

velikii [3]

We can use the point-slope equation:
$y = mx + b$
m, the slope, is 3/4:
$y = \frac{3}{4} x + b$
To find b, we plug in the point (4,1/3):
$( \frac{1}{3} ) = \frac{3}{4} (4) + b \\ \frac{1}{3} = 3 + b \\ \frac{1}{3} = \frac{9}{3} + b$
$- \frac{8}{3} = b$

Therefore, the point-slope equation is
$y = \frac{3}{4} x - \frac{8}{3}$

Now we have to see which answer matches.

$y - \frac{3}{4} = \frac{1}{3} (x - 4) \\ y - \frac{3}{4} = \frac{1}{3} x - \frac{4}{3} \\ y - \frac{9}{12} = \frac{1}{3} x - \frac{16}{12}$
$y = \frac{1}{3} x - \frac{7}{12}$
Since this is not the same, we try the next one.

$y - \frac{1}{3} = \frac{3}{4} (x - 4) \\ y - \frac{1}{3} = \frac{3}{4} x - 3 \\ y - \frac{1}{3} = \frac{3}{4} x - \frac{9}{3}$
$y = \frac{3}{4} x - \frac{8}{3}$

This is the same, so this is the answer. We should still double-check the other answers.

$y - \frac{1}{3} = 4(x - \frac{3}{4} ) \\ y - \frac{1}{3} = 4x - 3 \\ y - \frac{1}{3} = 4x - \frac{9}{3}$
$y = 4x - \frac{8}{3}$
This one is not equivalent.

$y - 4 = \frac{3}{4} (x - \frac{1}{3} ) \\ y - 4 = \frac{3}{4} x - \frac{1}{4} \\ y - \frac{16}{4} = \frac{3}{4} x - \frac{1}{4}$
$y = \frac{3}{4} x + \frac{15}{4}$
This one also does not work.

The answer is the second one:
$y - \frac{1}{3} = \frac{3}{4} (x - 4)$

3 0

3 years ago

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The volume of a cone varies jointly as the height of the cone and the area of the base. The volume of a cone with height 30 cent

irina [24]

Answer:

V₂=28cm³

Step-by-step explanation:

The volume of a cone is $V=\frac{\pi r^{2}h}{3}$ , and h₁ = 30 cm but the base (Ba₁) is 14 cm², so

$V=\frac{Ba.h}{3}$ , where Ba= Base area

if h₂=7cm and Ba₂=12cm² then

$V_{1} =\frac{12cm^{2}.7cm}{3}=28cm^{3}$

If the volume of a cone varies jointly as the height of the cone and the area of the base, then we must find the relationship between the bases and heights of the cones

Ba₁*h₁ = 30cm*14cm² = 420cm³

Ba²*h²= 7cm*12cm² = 84cm³

420/84 = 5; ratio = 5 also

V₂=V₁/5 ⇒ V₂=140cm³/5 = 28cm³

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3 years ago

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antiseptic1488 [7]

Answer:

$a_{27}=-115$