May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Answer:
9d you need to take the 3 to the power outside the (). I can't read it. 4???
10c x needs to be raised to the power also.
10e simplify the fraction
Step-by-step explanation:
Answer:
The right answer is "
".
Step-by-step explanation:
The given values are:
As we know,
95% confidence for 
will be:
= 
The lower bound will be:
= 
= 
The upper bound will be:
= 
= 
Thus the right answer is ""
<span>x(1^2)-2(1)+4(1^3)=6
x - 2 + 4 = 6
x + 2 = 6
x = 4 </span>
