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3 years ago

Imani won 50 super bouncy balls playing

Mathematics

1 answer:

pantera1 [17]3 years ago

8 0

Answer:

Step-by-step explanation:

50-2= 48

48 divide by 2 is 16

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Express each of the following in logarithmic form

vodomira [7]

Answer:

See explanation.

Step-by-step explanation:

(i) 5^3 = 125

log 5^3 = log 125

Using the rule log a^n = n log a

3 log 5 = log 125.

(ii) 3^-2 = 1/9

-2 log 3 = log 1/9

(iii) 10^-3 = 0.001

-3 log 10 = log 0.001

(iv) 81^3/4 = 27

3/4 log 81 = log 27.

5 0

3 years ago

Read 2 more answers

Perform the multiplication, (7x2+a2)(x2–3a2)

aksik [14]

Answer:

The given multiplied expression is

$(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

Step-by-step explanation:

Given expression is $(7x^2+a^2)(x^2-3a^2)$

To find the multiplication of the given expression :

$(7x^2+a^2)(x^2-3a^2)$

By using the distributive property to solve the given expression as below

$(7x^2+a^2)(x^2-3a^2)=(7x^2)(x^2)+(7x^2)(-3a^2)+(a^2)(x^2)+(a^2)(-3a^2)$

$=7x^2.x^2-21x^2a^2+a^2x^2-3a^2.a^2$

$=7x^{2+2}-21x^2a^2+a^2x^2-3a^{2+2}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$=7x^4-21x^2a^2+a^2x^2-3a^4$

Adding the like terms in the above expression we get

$=7x^4-20x^2a^2-3a^4$

Therefore $(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

Therefore the given multiplied expression is

$(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

8 0

3 years ago

I need to calculate the speed of light can someone give me an equation for doing so?

Umnica [9.8K]

Answer:

sorry dont know

Step-by-step explanation:

7 0

3 years ago

How do you write 287% as a fraction or mixed number in simplest form? Submit

Anna007 [38]

As a fraction: 287/100

As a mixed number: 2 87/100

_____
Remember, "%" means exactly the same thing as "/100".

3 0

3 years ago

I need help on this it’s about trig identities

Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

$\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha$

$\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha }{cos\alpha (1 + sin\alpha) }$

$\frac{1 + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha }{cos\alpha + sin\alphacos\alpha }$

$\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha }$

$\frac{2(1 + sin\alpha) }{cos\alpha(1 + sin\alpha ) }$

$\frac{2}{cos\alpha }$

2sec $\alpha$

2.-

sec²x - tanxsecx

$\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}$

$\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}$

$\frac{1 - sinx}{cos^{2}x }$

$\frac{1 - sinx}{1 - sin^{2}x }$

$\frac{1 - sinx}{(1 - sinx)(1 + sinx)}$

$\frac{1}{1 + sinx}$

3 0

3 years ago