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AleksAgata [21]
3 years ago
7

How will you find the distance between these two points using Pythagorean theorem?

Mathematics
1 answer:
kow [346]3 years ago
3 0
R represents radius or the distance between two points, the pythagorean expression will be
r² = Δx² + Δy²
Δ means the change, Δx means the change of x, Δy means the change of y

Given:
(x₁,y₁) = (-5,-1)
(x₂,y₂) = (0,2)

Input the numbers to the expression
r² = Δx² + Δy²
r² = (x₂ - x₁)² + (y₂ - y₁)²
r² = (0 + 5)² + (2 + 1)²
r² = 5² + 3²
r² = 25 + 9
r² = 34
r = √34

The distance is √34 unit length
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F'(-7, 13) was dilated by a scale factor of 2 about (-2, -5), the resulting image is___
AveGali [126]

The resulting image of the point F(x, y) = (- 7, 13) is F'(x, y) = (- 12, 31).

<h3>What is the resulting image of a point by rigid transformation?</h3>

In this problem we have a point that has to be transformed by a kind of rigid transform known as dilation, which is defined by the following equation:

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]             (1)

Where:

  • O(x, y) - Center of dilation
  • P(x, y) - Original point
  • P'(x, y) - Image
  • k - Scale factor

If we know that O(x, y) = (- 2, - 5), F(x, y) = (- 7, 13) and k = 2, then the resulting image is:

F'(x, y) = (- 2, - 5) + 2 · [(- 7, 13) - (- 2, - 5)]

F'(x, y) = (- 2, - 5) + 2 · (- 5, 18)

F'(x, y) = (- 2, - 5) + (- 10, 36)

F'(x, y) = (- 12, 31)

The resulting image of the point F(x, y) = (- 7, 13) is F'(x, y) = (- 12, 31).

To learn more on rigid transformations: brainly.com/question/28004150

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3 0
2 years ago
Find the volume of the triangular prism <br> Thank you!!
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
Triangle A = 12 bh<br>Find the area<br>of the triangle<br>base 15in height 3in<br>A =​
Morgarella [4.7K]

Answer:

The correct answer is 22.5 in^2

3 0
3 years ago
You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl
gtnhenbr [62]

Answer:

maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

Step-by-step explanation:

We know that area of circle is given by

A=\pi \times (radius)^{2}

For circle with radius 'r' we have

A_{1}=\pi \times (r)^{2}

For circle with radius 'R' we have

A_{2}=\pi \times (R)^{2}

Now according to given condition we have

A_{1}-A_{2}\leq \frac{5}{\pi }

\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}

Thus maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

6 0
4 years ago
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