Answer:
α = 62°
β = 56°
gamma = 90°
Step-by-step explanation:
ΔAOB is isosceles, so m∠A = m∠ABO = 28
28 + 28 + m∠AOB = 180
m∠AOB = 180 - 28 - 28 = 124
β = 180 - 124 = 56
arcAB = 124
ΔBOC is isosceles. α = m∠BCO = 1/2(arc AB) = 1/2(124) = 62
∠D is inscribed in a semicircle
m∠D = gamma = 90°
Answer:
90 or 85
Step-by-step explanation:
it is a right angle, and all the sides must add up to 180 degrees so yes, 85, im pretty sure.
To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
Answer:
A=20 degrees
D=70 degrees
E=110 degrees
Step-by-step explanation:
A=20 because a right angle always = 90 so 90-70=20
D=70 because I believe that angles C and D make a right angle, and C = 20 degrees, so we now subtract. 90-20=70
E=110 because D and E = a straight line, which is 180, and sense D is 70 degrees, all we need to do is subtract. 180-70 is 110, so our answer is 110
Hoped this helped, and let me know if I messed up somewhere.
