1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Find the mode of 3, 6, 4, 3, 2, 4, 7, 8, 6, 3, 9
lions [1.4K]
Answer:
3 is the mode because it appears most often.
Step-by-step explanation:
Answer:
-2x + 3
Step-by-step explanation:
-5x/5 - 20/5 - 4x/4 + 28/4 ➡-x - 4 -x +7 ➡-2x + 3
Answer:
The 6 people would each get 5lb. of beans. 5 lies between 4 and 6.
Step-by-step explanation:
To get the answer to this problem, all you have to do is divide the total pounds of beans by how many people there are. 30 ÷ 6= 5, so each person would get 5 pounds. Since 5 comes between 4 & 6, you can use that as your answer.
