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2 years ago

Plz help will be marked BRAINLIEST Thanks !

Mathematics

2 answers:

zloy xaker [14]2 years ago

6 0

Answer:

The first two

Step-by-step explanation:

Do the parenthesis of the first and you will get the original equation.

Multiple the second with 4 and you will get the original equation too.

nataly862011 [7]2 years ago

5 0

^ Their answer is correct, the first two

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I need help with this problem,

emmasim [6.3K]

Answer:

JL = 78

Step-by-step explanation:

The shorter segment is a midline, so is half the length of the longer one.

2(5x-16) = 4x +34

5x -16 = 2x +17 . . . . . divide by 2

3x = 33 . . . . . . . . . . add 16-2x

x = 11 . . . . . . . . . . divide by 3

Then segment JL is ...

JL = 4x +34 = 4(11) +34 = 44+34

JL = 78

4 0

1 year ago

The points -4. -4 -4, 4

Ilia_Sergeevich [38]

Answer:

whats the question?

Step-by-step explanation:

I don't get the question so what is the question?

3 0

2 years ago

Use algebraic means to show that x^2 + y^2 = 8 is not a function. Explain your process.

11Alexandr11 [23.1K]

Answer:

For a single value of x function has more than one corresponding value of y which satisfies the equation.

Step-by-step explanation:

Function: A relationship between a set of inputs and a set of possible outputs, where exactly one output is associated with each input.

It means for an equation to represent a function any single value of x there should be only one corresponding value of y which satisfies the equation.

Now consider the given equation.

$x^2 + y^2 = 8$

If we put x=0 then we get two value of y i.e $\sqrt8$ and $-\sqrt8$ which satisfy the equation and therefore the equation is not a function.

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3 years ago

Given 5n² + 6n + 7 = n² - 4n : a. Find the value of the discriminant. b. State the number and type of roots/solutions/zeros.[2 r

Vika [28.1K]

$\bf 5n^2+6n+7=n^2-4n\implies 5n^2+6n+7-n^2+4n=0
\\\\\\
4n^2+10n+7=0\\\\
-------------------------------\\\\
\begin{array}{llccll}
&{{ 4}}x^2&{{ +10}}x&{{ +7}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}$

if you get a positive value, that means 2 real solutions
if you get 0, means 1 real solution only
if you get a negative value, is an imaginary root solution, same as saying no solution.

4 0

2 years ago

I just wanted to make sure what I'm doing is right

Olin [163]

You're doing it exactly right! Keep on going! :)

6 0

3 years ago