Answer:
Yes
Step-by-step explanation:
85, 85, 90, 90, 95, 95, 100, 100, 150
Median: 95
Q1: (85+90)/2 = 87.5
Q3: 100
IQR: Q3 - Q1 = 100 - 87.5 = 12.5
1.5 × IQR = 18.75
Outliers are outside the interval:
[Q1 - 1.5×IQR, Q3 + 1.5×IQR]
Q3 + 1.5IQR = 100 + 18.75
= 118.75
Since 150 > 118.75, it is an outlier
Answer: 14.29%
Step-by-step explanation:
Let C be the cost of 1 article and S the selling price for 1 article. The profit, P, for 1 article would be:
P = S - C
For n articles, the total profit would be
nP = nS - nC
Profit percentage would be (P/S)*100%
---------------------------------------------------------
We know that 21C = 18S: This can be written as C = (18/21)S
P = S - C
P = S - (18/21)S
P = (3/21)S or P=(1/7)S
Profit percentage would therefore be
(P/S)*100%
((1/7)S/S)*100%
(1/7)*100%
= 14.29%
Do the same graph but inversed, kind of like when you see yourself in a mirror
Answer:
√10 / 10
Step-by-step explanation:
tan θ > 0 and sin θ < 0, so θ is in quadrant III. That means cos θ < 0.
cos(θ + π/4)
Use angle sum formula.
cos θ cos(π/4) − sin θ sin(π/4)
½√2 cos θ − ½√2 sin θ
Factor.
½√2 cos θ (1 − tan θ)
½√2 cos θ (1 − 2)
-½√2 cos θ
Write in terms of secant.
-½√2 / sec θ
Use Pythagorean identity (remember that cos θ < 0).
-½√2 / -√(1 + tan²θ)
-½√2 / -√(1 + 2²)
½√2 / √5
√10 / 10
