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3 years ago

Factor the expression completely. x^2y^4-x^5y^2

Mathematics

1 answer:

Rzqust [24]3 years ago

3 0

Answer:

The answer to your question is x²y²(y² - x³)

Step-by-step explanation:

To solve this problem look for the Greatest common factor of both terms.

The maximum x that can be factor = x²

The maximum y that can be factor = y²

Factor the binomial by common factor technique

x²y²(y² - x²)

It can not factor more.

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Are the functions linear or nonlinear?

inna [77]

Linear. They all follow the format y=mx+c wether or not they have been rearranged.

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3 years ago

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Factor the following problems SHOW YOUR WORK<br> 1. x^2+16x+24<br> 2. x^2-10a+25

Juliette [100K]

There is no work to show. It is really just trial and error till you get the hang of it. You look at the multiples of the last term and find.which add or subtract to the middle terms coefficient. Use DeCartes law of signs to determine if it is plus or minus.
1. Does not factor solve using other method
2. (X-5)^2

7 0

3 years ago

Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o

GREYUIT [131]

Answer:

And then we can conclude that the middle 75% values of her lap times are from a=126.835 to b=132.585

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Solution to the problem

Let X the random variable that represent the times of a population, and for this case we know the distribution for X is given by:

$X \sim N(129.71,2.5)$

Where $\mu=129.71$ and $\sigma=2.5$

Since we want the middle 75% values then on tha tails we need 1-0.75 =0.25 or 25% of the data and since the distribution is symmetric we need 12.5 % of the values on each tail.

For this part we want to find a value a and b, such that we satisfy this condition:

$P(X>b)=0.125$ (a)

$P(X$ (b)

We can use the z score formula in order to find the value a and b given by:

$z=\frac{x-\mu}{\sigma}$

As we can see on the figure attached the z value that satisfy the condition (b) with 0.125 of the area on the left and 0.875 of the area on the right it's z=-1.15. On this case P(Z<-1.15)=0.125 and P(z>-1.15)=0.875

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-1.15$

And if we solve for a we got

$a=129.71 -1.15*2.5=126.835$

So the value of height that separates the bottom 12.5% of data from the top 87.5% is 126.835.

As we can see on the figure attached the z value that satisfy the condition (b) with 0.875 of the area on the left and 0.125 of the area on the right it's z=1.15. On this case P(Z<1.15)=0.875 and P(Z>1.15)=0.125

If we use condition (b) from previous we have this:

$P(X>b)=P(\frac{X-\mu}{\sigma}>\frac{b-\mu}{\sigma})=0.125$