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alexdok [17]
3 years ago
14

Factor the following problems SHOW YOUR WORK 1. x^2+16x+24 2. x^2-10a+25

Mathematics
1 answer:
Juliette [100K]3 years ago
7 0
There is no work to show. It is really just trial and error till you get the hang of it. You look at the multiples of the last term and find.which add or subtract to the middle terms coefficient. Use DeCartes law of signs to determine if it is plus or minus.
1. Does not factor solve using other method
2. (X-5)^2
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Answer:

angle JKL is 106

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an isosceles triangle means two sides are the same and the bottom two angles are the same length. So you would equal the two equations and solve it to get x. Then replace one of the equation's x with the number you got, which would be 5, and solve that. Since both bottom angle are the same, the other angle would be the same degree, 37*. A triangle is 180* total, so subtract that by two 37's and you'll get the answer.

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3 years ago
Tyson wrote this expression to describe the total amount of points he won in both rounds of a game.
Rainbow [258]
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3 years ago
Simplify the following expression using imaginary numbers. Express your answer in a + bi form
mamaluj [8]
<h2>Answer:</h2>

0 - 17i

<h2>Step-by-step explanation:</h2>

Given expression;

i⁸⁰ + i³⁸ - i17

To express the expression in the form a+bi;

<em>i. Rewrite the expression such that it contains terms in i²</em>

(i²)⁴⁰ + (i²)¹⁹ - i17

<em>ii. Solve the result from (i) above using the identity i² = -1</em>

We know that the square root of -1 is i. i.e

\sqrt{-1} = i

<em>Squaring both sides gives</em>

<em>=> </em>(\sqrt{-1} )^{2} = i^{2}<em />

=> -1 = i²

Therefore,

i² = -1

<em>Substitute i² = -1 in step (i) above</em>

(-1)⁴⁰ + (-1)¹⁹ - i17

<em>(iii) Solve the result in (ii)</em>

We know that the when a negative number is raised to the power of an even number, the result is a positive number. If it is raised to the power of an odd number, the result is a negative number. Therefore,

(-1)⁴⁰ + (-1)¹⁹ - i17 becomes

1 + (-1) - i17

0 - i17

<em>(iv) Write the result from (iii) in the form a+bi</em>

0 - 17i

5 0
3 years ago
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