The graph of a linear function intersects with the x axis at a point with an abscissa of 4 and with the y axis at a point with a
n ordinate of 11. Write the formula of the function.
1 answer:
We know that
points are
x intercept
A (4,0)
y intercept
B (0,11)
step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4
with m and the point B (0,11)
y-y1=m*(x-x1)
y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11
the answer is
<span>the formula of the function is
</span>y=-(11/4)x+11
see the attached figure
points are
x intercept
A (4,0)
y intercept
B (0,11)
step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4
with m and the point B (0,11)
y-y1=m*(x-x1)
y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11
the answer is
<span>the formula of the function is
</span>y=-(11/4)x+11
see the attached figure
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