The graph of a linear function intersects with the x axis at a point with an abscissa of 4 and with the y axis at a point with a
n ordinate of 11. Write the formula of the function.
1 answer:
We know that
points are
x intercept
A (4,0)
y intercept
B (0,11)
step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4
with m and the point B (0,11)
y-y1=m*(x-x1)
y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11
the answer is
<span>the formula of the function is
</span>y=-(11/4)x+11
see the attached figure
points are
x intercept
A (4,0)
y intercept
B (0,11)
step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4
with m and the point B (0,11)
y-y1=m*(x-x1)
y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11
the answer is
<span>the formula of the function is
</span>y=-(11/4)x+11
see the attached figure
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The series converges to 1/(1-9x) for -1/9<x<1/9
Given the series is ∑
We have to find the values of x for which the series converges.
We know,
∑ converges to (a) / (1-r) if r < 1
Otherwise the series will diverge.
Here, ∑ is a geometric series with |r| = | 9x |
And it converges for |9x| < 1
Hence, the given series gets converge for -1/9<x<1/9
And geometric series converges to a/(1-r)
Here, a = 1 and r = 9x
Therefore, a/(1-r) = 1/(1-9x)
Hence, the given series converges to 1/1-9x for -1/9<x<1/9
For more information about convergence of series, visit
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