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Arturiano [62]
2 years ago
8

Find all values of x for which the series converges. (enter your answer using interval notation. ) [infinity] (4x)n n = 1

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
8 0

The series converges to  1/(1-9x) for -1/9<x<1/9                  

Given the series is  ∑ 9x^{n} x^{n}

We have to find the values of x for which the series converges.

We know,                

∑ ar^{n-1}    converges to  (a) / (1-r) if r < 1

Otherwise the series will diverge.

Here, ∑ (9x)^{n} is a geometric series with |r| = | 9x |

And it converges for |9x| < 1

Hence, the given series gets converge for -1/9<x<1/9

And geometric series converges to a/(1-r)

Here, a = 1 and r = 9x

Therefore, a/(1-r) = 1/(1-9x)

Hence, the given series converges to   1/1-9x  for  -1/9<x<1/9

For more information about convergence of series, visit

brainly.com/question/15415793

#SPJ4

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Answer:

  8 bags of pretzels

Step-by-step explanation:

Let x represent the number of bags of pretzels Tim buys. We assume he spends exactly $20 on exactly 12 bags of snack food. Then his purchase is ...

  1.50x + 2.00(12-x) = 20.00

  -0.50x +24.00 = 20.00 . . . eliminate parentheses, collect terms

  -0.50x = -4.00 . . . . . . . . . . .subtract 24

  x = 8 . . . . . . . . . . divide by -0.50

Tim will buy 8 bags of pretzels.

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3 years ago
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klemol [59]

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Step-by-step explanation:

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3 years ago
Suppose the solutions of a homogeneous system of four linear equations in five unknowns are all multiples of one nonzero solutio
Akimi4 [234]

Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.

Yes, it's miles true.

Consider the machine as Ax = 0. in which A is 4x5 matrix.

From given dim Nul A=1. Since, the rank theorem states that

The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation

rank A+ dim NulA = n

dim NulA =n- rank A

Rank A = 5 - dim Nul A

Rank A = 4

Thus, the measurement of dim Col A = rank A = five

And since Col A is a subspace of R^4, Col A = R^4.

So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.

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3 years ago
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6 0
3 years ago
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What is the following quotient? StartFraction RootIndex 3 StartRoot 60 EndRoot Over RootIndex 3 StartRoot 20 EndRoot EndFraction
FrozenT [24]

Answer:

\sqrt[3]{3}

Step-by-step explanation:

We are required to simplify the quotient: \dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}

Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:

\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}

=\sqrt[3]{3}

The simplified form of the given quotient is \sqrt[3]{3}.

6 0
3 years ago
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