I would say either a or b
The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then

For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is

The distribution is graphed as shown below.
Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.
Answer:
Step-by-step explanation:
3. function
4. not a function
5. function
6. not a function
7. function
8. not a function
Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
By the Fundamental Theorem of Arithmetic, all number can be expressed as a product of prime numbers.
So naturally, lets divide 120 by an easy prime number.
We know that 120 is even, so lets try 2
120/2 = 60
lets keep dividing it by two until it becomes odd or prime
60/2 = 30
30/2 = 15
now lets see, what are some factors of 15?
Well the obvious ones are 3 and 5, both of which are prime. So now we can just count up how many times we divided it by 2
120/2 = 60
60/2 = 30
30/2 = 15
and 15 is just 3 x 5, so:
<span>
120=(<span>23</span>)×(3)×(5)</span>
or
<span><span>
120 = 2 × 2 × 2 × 3 × 5</span></span>