The value is positive six
Answer:
Step-by-step explanation:
Given




Required

The question is illustrated with the attached image.
From the image, we have:

This gives:


--- approximated
Answer:
Input Data :
Point 1(xA,yA)(xA,yA) = (4, 3)
Point 2(xB,yB)(xB,yB) = (3, -2)
Objective :
Find the distance between two given points on a line?
Formula :
Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2
Solution :
Distance between two points = √(3−4)2+(−2−3)2(3-4)2+(-2-3)2
= √(−1)2+(−5)2(-1)2+(-5)2
= √1+251+25
= √2626 = 5.099
Distance between points (4, 3) and (3, -2) is 5.099
Answer:
Well, assuming that these are cubes labeled 1-6, there is a 1/12 chance of the sum equaling 2, since they would both have to land on 1
Step-by-step explanation: