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NikAS [45]
3 years ago
15

At the fair,Kate found a strange machine with a sign on it labeled, enter a number. When she pushed the number 15, the machine d

isplayed 17. Perplexed she tried 100, and the machine displayed 94. What is the machine doing?
Mathematics
1 answer:
Ivan3 years ago
6 0

apparently subtracting 6

15-6=9

23-6=17

100-6=94

77-6=71

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Classify the function as a linear or quadratic and identify the quadratic, linear, and constant terms. y=(3x+4)(-2x-3)
Troyanec [42]

Answer:

The function is quadratic

Step-by-step explanation:

I just took the quiz and I Had a passing score

3 0
3 years ago
Two rays that intersect at a right angle are best described as which of the following
sveticcg [70]

A coplanar point are points that lie on the same line. An angle is the intersection of two noncollinear rays at a common endpoint. The rays are called sides and the common endpoint is called the vertex.


hope that helps


7 0
3 years ago
Read 2 more answers
Boxes of raisins are labled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is re
kati45 [8]

Answer:

The 99 % confidence interval on the basis of mean is ( 21.7393  ;   22.0257)

Step-by-step explanation:

Mean = Sum of observations / Number of observations

Mean = 21.88 +21.76 +22.14 +21.63+ 21.81 +22.12+ 21.97+ 21.57+ 21.75+ 21.96 +22.20 +21.80/ 12

Mean =x`= 262.59/12=  21.8825

Standard Deviation = s= ∑x²/n - ( ∑x/n)²

∑x²/n= 478.7344 +473.4976 + 490.1796+467.8569+ 475.6761 + 489.2944+ 482.6809+ 465.2649+ 473.0625+ 482.2416 +492.84 + 475.24/ 12

∑x²/n= 5746.5689/12= 478.8807 = 478.881

Standard Deviation = s= ∑x²/n - ( ∑x/n)²

s= 478.881- (21.8825)²= 478.881-478.843= 0.037

The confidence limit 99% for the mean will be determined by

x` ± α(100-1) √s/n

Putting the values in the above equation

= 21.8825 ± 2.58 √0.037/12

Solving the square root

= 21.8825 ± 2.58 (0.05549)

Multiplying the square root with 2.58

=21.8825 ± 0.1432

Adding and subtracting would give

21.7393  ;   22.0257,

Hence the 99 % confidence interval on the basis of mean is ( 21.7393  ;   22.0257)

5 0
3 years ago
The sugar content of the syrup is canned peaches is normally distributed. Assumethe can is designed to have standard deviation 5
andreyandreev [35.5K]

Answer: 0.50477

Step-by-step explanation:

Given : The sugar content of the syrup is canned peaches is normally distributed.

We assume the can is designed to have standard deviation \sigma=5 milligrams.

The sampling distribution of the sample variance is chi-square distribution.

Also,The data yields a sample standard deviation of s=4.8 milligrams.

Sample size : n= 10

Test statistic for chi-square :\chi^2=\dfrac{s^2(n-1)}{\sigma^2}

i.e. \chi^2=\dfrac{(4.8)^2(10-1)}{(5)^2}=8.2944

Now, P-value = P(\chi^2>8.2944)=0.50477  [By using the chi-square distribution table for p-values.]

Hence, the chance of observing the sample standard deviation greater than 4.8 milligrams = 0.50477

8 0
3 years ago
Multiply and subtract
WITCHER [35]

Answer:

26x³ - 12x² + 5x + 7

Step-by-step explanation:

  1. (2x³ - 3x + 11) - (3x² + 1) x (4 - 8x)
  2. 2x³ - 3x+11 - (12x² - 24x³ + 4 - 8x)
  3. 2x³ - 3x + 11 - 12x² + 24x³ - 4 + 8x
  4. 26x³ + 5x + 7 - 12x²

= 26x³ - 12x² + 5x + 7

4 0
3 years ago
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