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aleksandr82 [10.1K]
3 years ago
5

What is 2/5 y + 1/5 x -0.2y-6+(-2)

Mathematics
1 answer:
Sliva [168]3 years ago
6 0

Answer:

\frac{y}{5} + \frac{x}{5}-8

Step-by-step explanation:

1)  Simplify 2 /5y to 2y/5.

\frac{2y}{5} + \frac{1}{5} x-0.2 y-6-2

2) simplify 1/5x to x/5.

\frac{2y}{5} +\frac{x}{5} -0.2y-6-2

3) Collect like terms.

(\frac{2y}{5} -0.2y) + \frac{x}{5} +(-6-2)

4) Simplify.

\frac{y}{5}+ \frac{x}{5} -8

<em><u>Therefor, the answer is </u></em><em><u>y/5 + x/5 -8</u></em>.

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Rewrite the following sentence as an equation.
SVEN [57.7K]

Answer:

3(2+x)=0

Step-by-step explanation:

<u>Here are some vocab words:</u>

Product: Multiplication

Sum: Addition

"A number": x

3(2+x)=0

6 0
3 years ago
a flomming tile has the shape of a parallelogram whose base is 24cm and height is 10 cm how many tiles are required to cove the
g100num [7]

Answer:

4 1/2 tiles are needed to cover this area

Step-by-step explanation:

Mathematically, the area of a parallelogram is the product of the base and the height

We have this as;

24 * 10 = 240 cm^2

So the area of a tile is this

The number of tiles that will cover the given area will be;

1080/240 = 4.5 tiles

4 0
3 years ago
the top of the Washington Monument is shaped like a rectangular pyramid. the pyramid top has an approximate width and length of
AveGali [126]

The volume of a rectangular pyramid

Given a rectangular pyramid of width W, length L, and Height H, the volume is

V=\frac{\text{WLH}}{3}

We have to assume the pyramid given in the question has a square shape of length and width of L=34.5 feet and W = 34.5 feet, and a height of H=55 feet, thus the volume is:

V=\frac{\text{34.5}\cdot34.5\cdot55}{3}=21,821.25ft^3

Correct choice: A

6 0
1 year ago
Which side lengths form a right triangle?
fredd [130]

Answer:

Answer:\huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{u} \huge\mathfrak\green{t} \huge\mathfrak\pink{i}\huge\mathfrak\purple{o}\huge\mathfrak\red{n}\huge\mathfrak\orange{➔}\ Pythagoras law:h²=p²+b²

needed to apply

4²+8²=12²

80≠144 not a right angled triangle

again

2²+√5²=3²

9=9/

<em><u>side</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>right</u></em><em><u> </u></em><em><u>angled</u></em><em><u> </u></em><em><u>triangle</u></em>

again

2²+2²=(√8)²

4+4=8

8=8

<em><u>side are a right angled triangle</u></em>

4 0
3 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
bezimeni [28]

Answer:

See explanation and results below.

Step-by-step explanation:

We have the following data:

Age​ (yr) when award was won Frequency 25​-34 31 35​-44 36 45​-54 12 55​-64 4 65​-74 6 75​-84 1 85​-94 2

If we order the data we got the following result. We assume that the midpoint is given by:

Midpoint= \frac{L.Limit +U.Limit}{2}

The Class.Width = U.Limit-L.Limit

And the limits are given by the lower and upper limit.

L.Limit  U.Limit Class W  Midpoint  Frequency   Limits

  25         34     34-25=9     29.5           31           [25-34]                

  35         44      44-35=9     39.5          36           [35-44]

  45         54      54-45=9     49.5           12           [45-54]

  55         64      64-55=9     59.5           4            [55-64]

  65         74       74-65=9     69.5           6            [65-74]

  75          84      84-75=9     79.5            1            [75-84]

  85          94      94-85=9     89.5           2           [85-94]

8 0
3 years ago
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