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Oksi-84 [34.3K]
3 years ago
14

How to use graphing to find the solutions to the system of equations?

Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0
Once ur lines are graphed, the solution is where the lines intersect. So by graphing however many equations u have, the point where they intersect is the solution....unless of course u have parallel lines, then there is no solution. And if ur lines are coincident, the same line on top of each other, then there is infinite solutions.
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the area of rectangle a is 11/12 square meters. the area of rectangle b is 8/12 square meters. how much larger is rectangle a?
tresset_1 [31]
11 / 12 - 8 / 12 = 3 / 12 = 1/4 square meters;
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If () = − 10, find (20)
Studentka2010 [4]

the correct answer to your question is 10

8 0
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Find the volume of the prism.<br> 3 ft<br> 7 ft<br> 5 ft
Taya2010 [7]

Answer:

105

Step-by-step explanation:

I am guess this prism is a rectangle

So 3 times 7 times 5 is 105

Thus the answer is 105

Hope this helps!

6 0
2 years ago
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topjm [15]

Answer:

0.12%

Step-by-step explanation:

<em>Percent</em><em> </em><em>mea</em><em>ns</em><em> </em><em>out</em><em> </em><em>of</em><em> </em><em>hun</em><em>dred</em>

<em>therefore</em><em> </em><em>2</em><em>6</em><em> </em><em>in</em><em> </em><em>perc</em><em>entage</em><em> </em><em>is</em><em> </em><em>wri</em><em>tten</em><em> </em><em>as</em>

<em>\frac{26}{100}  = 0.26</em>

<em>=</em><em>0</em><em>.</em><em>2</em><em>6</em><em>%</em>

<em>and</em><em> </em><em>1</em><em>4</em><em> </em><em>in</em><em> </em><em>perc</em><em>entage</em><em> </em><em>is</em><em> </em><em>wri</em><em>tten</em><em> </em><em>as</em>

<em>\frac{14}{100}</em>

<em>=</em><em>0</em><em>.</em><em>1</em><em>4</em><em>%</em>

<em>perce</em><em>nt</em><em>age</em><em> </em><em>differ</em><em>ence</em><em> </em><em>bet</em><em>ween</em><em> </em><em>2</em><em>6</em><em> </em><em>and</em><em> </em><em>1</em><em>4</em><em> </em><em>,</em><em> therefore</em>

<em>=</em><em>0</em><em>.</em><em>2</em><em>6</em><em>%</em><em> </em><em>-</em><em> </em><em>0</em><em>.</em><em>1</em><em>4</em><em>%</em>

<em>=</em><em>0</em><em>.</em><em>1</em><em>2</em><em>%</em>

6 0
3 years ago
PLEASE PLEASE HELP ME PLEASE<br> Which radical expressions are equivalent to
VikaD [51]

Answer:

D and E

Step-by-step explanation:

Using the rule of radicals

a^{\frac{m}{n} } ⇔ \sqrt[n]{a^{m} }

Given

3^{\frac{4}{7} }

= (\sqrt[7]{3})^4 → D or

= \sqrt[7]{3^{4} } = \sqrt[7]{81} → E

7 0
3 years ago
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