Answer:
solving by substitution: t = -9, r = -6
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
Explanation: The GCF of 56 and 64 is 8 , as 8 goes into 56 exactly 7 times and into 64 exactly 8 times. 8(8)+7(8)=8(7+8).
Answer: The maximum revenue is $7482 . To get a maximum yield , The number of trees per acre needed is 43.
Step-by-step explanation:
Solution:
Let x represent the extra tree
So for an additional tree the yield of each tree will decrease by 4 bushels.
(80 +x)(26-4x) by expanding
2080 - 320x +26x -4x^2
Using x= -b/2a
X= 294/ -8
X= - 36.75
So apparently he currently has far too many trees per acre. To get the maximum yield , she needs to reduce the number of trees per acre by 36.75
So the number of trees per acre for maximum yield is
80-36.75
=43.25
Approximately x=43
So by reducing he get extra bushel in the tune of 174.
Total revenue= 174 ×43× 1$
=$7482
Answer:
26 students per classroom
Step-by-step explanation:
To solve this, the ratio 234 students:9 classrooms must be converted to:
s students:1 classroom
To convert the ratio, 9 was divided by 9 to get 1, and so you must also divide 234 by 9 to maintain the same ratio, which gives us the answer:
26 students: 1 classroom
Answer: 119
Step-by-step explanation: if it’s 1:7,
then you’d have to do 17x7
