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Fudgin [204]
3 years ago
10

Nicole has a collection of dolls that each weigh 2/10 grams. How much would 4/5 dolls weigh? Need answer NOW

Mathematics
1 answer:
dangina [55]3 years ago
8 0
.16 grams or 4/25 grams
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I need help with both of these problems. Thank you!
Dmitry [639]

Answer:

  1. 10
  2. 15ab

Step-by-step explanation:

1. The square of the binomial is ...

  (* -2m)^2 = *^2 -4m* +4m^2

Matching terms, you find ...

  *^2 = 100

  -4m* = -40

Both of these equations tell you the value of * is 10.

___

2. Same deal. Multiply ou the square and see what you have.

  (3a +2.5b)^2 = 9a^2 +15ab +6.25b^2

The term missing on the right side of the given equation is 15ab.

3 0
4 years ago
Find the length of the hypotenuse. a=20 in b=21in c=? SHOW WORK
Ulleksa [173]

Answer:

41 or 20

Step-by-step explanation:

good luck

follow me for more:>

3 0
3 years ago
Read 2 more answers
Help me please and thank you :)
____ [38]

Answer:

 A. 74 cm

Step-by-step explanation:

First, we break the rhombus down into similar shapes,

The area of 2 triangles = The area of a square

So we take the triangle from the left and combine it with the triangle on the right, it should make a rectangle, Then calculate the area of the rectangle,

10 multiplied by 5 =50

Thats the area of rectangle 1

Rectangle 2

3 multiplied by 6 = 18

Triangle

4 times 3 divided by 2 = 6

Thus

6 + 18 + 50  = 74

PLEASE GIVE BRAINLIEST AND 5 STARS.

5 0
3 years ago
Read 2 more answers
Simplify the expression using positive exponents. <br><br> 5^9 ⋅ 5^3
uranmaximum [27]
5^12 is the answer for this question
7 0
3 years ago
Read 2 more answers
Is each biconditional statement true or false?
Margarita [4]

Answer: 1. False

2. True

3. True

4.False


Step-by-step explanation:

1. False, because 6 is a multiple of 3 but 6 is not an odd number.

2. True, all even numbers are multiple of 2, and thus divisible by 2. Any number that is divisible by 2 must be a multiple of 2. hence,the given biconditional statement in true.

3. True, all multiples of 5 has 0 or 5 in the ones place.

Thus the given biconditional statement is true.

4.False, because 6 is not a multiple of 4 but 6 is not a prime number.

3 0
3 years ago
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