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4 years ago

What is the education of $15 a day to visit the fun factory ?

Mathematics

1 answer:

Burka [1]4 years ago

6 0

Given that the price per day is $15, to make an expression, all you’d have to do is plug in how many days you spent at fun factory to figure out how much money was spent

Here is the expression: 15x

Here is an example: 15 x 3 (plug in 3 for x)

15 x 3 = 45

Making 3 days a total of $45 dollars

Hope this helps you

Brainliest would be appreciated!

-AaronWiseIsBae

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Find the solution of this system of equations<br> - 2x + 10y = -22<br> -2x - 4y = 6

LenaWriter [7]

Answer:

x = 1, y = -2

Step-by-step explanation:

- 2x + 10y = -22 _______(1)

-2x - 4y = 6 _______(2)

From (1),

10y + 22 = 2x

x = (10y + 22) / 2

x = 5y + 11 .______(3)

Substitute (3) into (2),

-2 ( 5y + 11) -4y = 6

-10y - 22 - 4y = 6

-14y = 6 + 22

-14y = 28

y = 28/ -14

y =-2

Substitute y = -2 into (3).

x = 5y + 11

x = 5(-2) + 11

x = -10 + 11

x = 1

Therefore, the solution is x = 1, y = -2.

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3 years ago

What characterizes a tragic work in literature or drama?

Reptile [31]

Answer : a judgement error
explanation:

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4 years ago

An automobile manufacturer obtains the microprocessors used to regulate fuel consumption in its automobiles from three microelec

Anastaziya [24]

Answer:

The probability that a randomly selected automobile manufactured by the company will have a defective microprocessor is 6.2 %.

Step-by-step explanation:

Given:

The probability of getting a microprocessor from firm A is, $P(A)=45\%=0.45$

The probability of getting a microprocessor from firm B is, $P(B)=30\%=0.30$

The probability of getting a microprocessor from firm C is, $P(C)=25\%=0.25$

Now, let event D be having a defective microprocessor at random.

So, as per the question,

Probability of producing a defective microprocessor from firm A is, $P(D/A)=6\%=0.06$

Probability of producing a defective microprocessor from firm B is, $P(D/B)=7\%=0.07$

Probability of producing a defective microprocessor from firm C is, $P(D/C)=5.5\%=0.055$

Now, probability of having a defective microprocessor when selected at random is given as:

$P(D)=P(A)\cdot P(D/A)+P(B)\cdot P(D/B)+P(C)\cdot P(D/C)\\P(D)=(0.45\times 0.06)+(0.30\times 0.07)+(0.25\times 0.055)\\P(D)=0.027+0.021+0.01375\\P(D)=0.06175\ or\ P(D)=0.06175\times 100\approx 6.2\%$