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3 years ago

What is the education of $15 a day to visit the fun factory ?

Mathematics

1 answer:

Burka [1]3 years ago

6 0

Given that the price per day is $15, to make an expression, all you’d have to do is plug in how many days you spent at fun factory to figure out how much money was spent

Here is the expression: 15x

Here is an example: 15 x 3 (plug in 3 for x)

15 x 3 = 45

Making 3 days a total of $45 dollars

Hope this helps you

Brainliest would be appreciated!

-AaronWiseIsBae

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Evaluate tan 30° without using a calculator by using ratios in a reference triangle.

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Answer: Root 3 / 3

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2 years ago

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3 years ago

In the given figure △ABC ≅△DEC. Which of the following relations can be proven using CPCTC ?

Serhud [2]

Option B:

$\overline{A B}=\overline{D E}$

Solution:

In the given figure $\triangle A B C \cong \triangle D E C$ .

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$\overline{AB }=\overline{DE}$ – – – – (1)

$\overline{B C}=\overline{EC}$ – – – – (2)

$\overline{ CA}=\overline{CD}$ – – – – (3)

$\angle ACB=\angle DCE$ – – – – (4)

$\angle ABC=\angle DEC$ – – – – (5)

$\angle BAC=\angle EDC$ – – – – (6)

Option A: $\overline{B C}=\overline{D C}$

By CPCTC proved in equation (2) $\overline{B C}=\overline{EC}$ .

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Therefore Option B is true.

Option C: $\angle A C B=\angle D E C$

By CPCTC proved in equation (4) $\angle ACB=\angle DCE$ .

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Option D: $\angle A B C=\angle E D C$

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5 0

3 years ago

I need help Please help.

asambeis [7]

Answer:

Step-by-step explanation:

Number of students 10

Problem 1. $625 for the bus hire per friday, So 625*4=$2500

Problem 2. 2500/25=$100 each for the whole 4 weeks

Problem 3.

10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each

20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each

30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each

41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each

Hope this is correct

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2 years ago

This question is not that hard but I’m getting rushed

Vsevolod [243]

14:21 one is the right answer

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2 years ago