First twelve numbers first term4 rule:add15,subtract10
1 answer:
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Answer:
19
Step-by-step explanation:
Let T be the set of positive integers less than 100 with a 9 in the ten's place.
T = {90, 91, 92, 93, 94, 95, 96, 97, 98, 99}
n(T) = 10
Let O be the set of positive integers less than 100 with a 9 in the one's place.
O = {9, 19, 29, 39, 49, 59, 69, 79, 89, 99}
n(O) = 10
The common element is 99.
The union of both sets is
Therefore, 19 positive integers are less than 100 those have at least one 9.