Your method is completely correct. The first term will be 6 and each subsequent term can be obtained by adding 6 to the previous one, meaning the common difference is 6. The number of terms is given by the highest number that is divisible by 6 and dividing it by 6; that is 996/6 = 166
Then we simply apply the formula for arithmetic sequence sum:
S = n/2 [2a₁ + (n - 1)d]
S = 166/2 [ 2(6) + (166 - 1)6]
S = 83,166
Answer:
-7/5
Step-by-step explanation:
5/7
= -7/5
Answer:
thank you i need that
Step-by-step explanation:
The answers are as follows.
a. 9x
In order to get this, you need to reevaluate 64 as a base of 4. Since 64 is equal to 4^3, we can rewrite the right side as
64^3x = (4^3)^3x = 4^9x
Which gives you the first answer.
b. 10
Similar to the first problem, we need to express 16 as a base of 2. 2^4 is equal to 16, so we use that in it's place and simplify.
16^5/2 = (2^4)^5/2 = 2^20/2 = 2^10
c. Sqrt(7.31)
This one is more simple. Raising something to a 1/2 power (.5) is the same as taking the square root.
