Answer:
1st ans
(8x+19)=(9x+9)(vertically opposite angle)
19-9=9x-8x
x=10
2nd ans
(3x-31)=(x+59)(exterior alternate angle)
3x-x=59+31
2x=90
x=90/2
x=45
3rd ans
(5x-33)+(6x+4)=180(straight angle )
11x-29=180
11x=180+29
x=209/11
x=19
With the curve
parameterized by
with
, and given the vector field
the work done by
on a particle moving on along
is given by the line integral
where
The integral is then
Answer:
28.35
Step-by-step explanation:
Answer:
a
4,5,8,11 are the domain
Step-by-step explanation:
x is always the domain, input and It could also be a function but I don't think that only four five eight and 11 are functions so I would go with a
Answer:
a) ∝A ∈ W
so by subspace, W is subspace of 3 × 3 matrix
b) therefore Basis of W is
={ }
Step-by-step explanation:
Given the data in the question;
W = { A| Air Skew symmetric matrix}
= {A | A = -A^T }
A ; O⁻ = -O⁻^T O⁻ : Zero mstrix
O⁻ ∈ W
now let A, B ∈ W
A = -A^T B = -B^T
(A+B)^T = A^T + B^T
= -A - B
- ( A + B )
⇒ A + B = -( A + B)^T
∴ A + B ∈ W.
∝ ∈ | R
(∝.A)^T = ∝A^T
= ∝( -A)
= -( ∝A)
(∝A) = -( ∝A)^T
∴ ∝A ∈ W
so by subspace, W is subspace of 3 × 3 matrix
A ∈ W
A = -AT
A =
=
therefore Basis of W is
={ }