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tatyana61 [14]
3 years ago
13

PLEASEEE HURRY Please please please

Mathematics
1 answer:
Andre45 [30]3 years ago
7 0

Answer:

final answer is: ABC, A (-5,1), B (-4,6) and C (-1,4)

Step-by-step explanation:

Original: ABC, A (2,-1), B (1,4) and C (-2,2)

translate 3 units to the right and 2 units up: ABC, A (5,1), B (4,6) and C (1,4)

reflected over the x-axis: ABC, A (5,-1), B (4,-6) and C (1,-4)

rotated 180°: ABC, A (-5,1), B (-4,6) and C (-1,4)

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I will give brainly help.
Burka [1]

Answer:

Company G charges 5 more dollars per hour than Company H.

5 0
2 years ago
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In 2001, the United States' oil consumption was 7,297.4 millions of barrels, while Japan's was 1,979.4 millions of barrels. How
AleksAgata [21]
The answer would be 5,318,000 more barrels were consumed by the U.S than Japan

5 0
3 years ago
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Which function is graphed below?<br><br>​
Masteriza [31]

Exponential Function.

y =  {a}^{x}  \:  \: (a > 0) \:  \: (a≠1)

Also the shown graph is a decreasing graph.

y =  {a}^{x}  \:  \: (0 < a < 1)

The equation above is the equation of the graph that is shown in the picture.

8 0
3 years ago
PLEASE NEEED HEELPP
krok68 [10]
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area. 
only A and E satisfy both inequality, in the overlapping shaded area.

 
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true. 
 for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities. 
Do the same for point E (5,-4)

Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area. 
8 0
3 years ago
Help help help please really need help
Galina-37 [17]

Problem 1

<h3>Answer:  B. M<3 would need to double.</h3>

Explanation: This is because angles 3 and 6 are congruent corresponding angles. Corresponding angles are congruent whenever we have parallel lines like this. If they weren't congruent, then the lines wouldn't be parallel. We would need to double angle 3 to keep up with angle 6.

=====================================================

Problem 2

<h3>Answer: D. none of these sides are parallel</h3>

Explanation: We have angles A and C that are same side interior angles, but they add to A+C = 72+72 = 144, which is not 180. The same side interior angles must add to 180 degrees for parallel lines to form. This shows AB is not parallel to CD.

A similar situation happens with angles B and D, since B+D = 108+108 = 216. This also shows AB is not parallel to CD. We can rule out choices A and C.

Choice B is false because AD is a diagonal along with BC. The diagonals of any quadrilateral are never parallel as they intersect inside the quadrilateral. Parallel lines never intersect.

The only thing left is choice D. We would say that AC || BD, since A+B = 72+108 = 180 and C+D = 72+108 = 180, but this isn't listed as an answer choice.

5 0
3 years ago
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