Are there any more choices? it looks like B because the graph is decreasing.
Answer:
Step-by-step explanation:
If the upper triangle has a right angle at Island C, we need only use the Pythagorean Theorem to find x:
(10 mi)^2 + (20 mi)^2 = x^2, so that
x^2 = 100 mi^2 + 400 mi^2 = 500 mi^2, which reduces to
x = +10√5 mi
Note that the shortest side (10 mi) is adjacent to a 30 degree angle. Thus, the upper triangle is a 30-60-90 triangle, meaning that the Pythagorean Theorem DOES apply here.
Next time, please incude ALL of the verbal instructions. Thank you.
Answer:
8626
Step-by-step explanation:
use a calculator in instead of here this was a EZ question but thanks for the points and if you have a harder question i'll be waiting
Unusual notation. I won't fuss with it.
a. We have isosceles PRT, so angle RPT = angle RTP.
By the definition of angle bisector, angle MTP = angle MTF, and angle MPT = angle MPU.
We have m angle RTP = m angle MTF + m angle MTP = 2 m angle MTP
Similarly, m angle RPT = 2 m angle MPT
2 m angle MTP = 2 m angle MPT
angle MPT = angle MPT
That's the first part.
b. That makes MPT isosceles.
c. 2x+124=180
2x = 56
x = 28 degrees
MTP = 28 degrees
d. We have angle RPT=angle RTP=56 so PRT=180-2(56)=68 degrees
PUT = 180 - UTP - UPT = 180 - 28 - 56 = 96 degrees
Bad drawing, PUT looks acute.
angle PRT = 68 degrees, angle PUT = 96 degrees
