Question

A satellite dish has cross-sections shaped like parabolas. The receiver is located 13 inches from the base along the axis of symmetry. If the satellite dish is 26 inches across at the opening, what is its depth in inches? (Round your answer to the nearest tenth if necessary.)

Answer 1

Answer:

Depth = 3.3 inches

Step-by-step explanation:

 Given that the shape of the satellite looks like a parabola

The equation of parabola is given as follows

$x^2=4\times a\times y$

Where

a= 13

Therefore

$x^2=4\times 13\times y$

$x^2=52\times y$

Lets take (13 , y) is a

Now by putting the values in the above equation we get

$13^2=52\times y$

$y=\dfrac{13^2}{52}=3.25$

y=3.25 in

Therefore the depth of the satellite at the nearest integer will be 3.3 inches.

Depth = 3.3 inches