<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.
To solve for
You first need to find a common denominator.
To do so, you need to make both denominators 10 by multiplying the top and bottom of
by 5
=
Reduce by dividing both the top and bottom by 2
Your answer is
Answer:
x = - 1
y = - 3
z = -2
Step-by-step explanation:
Please see steps in the image attached here.
Answer:
97/139
Step-by-step explanation:
You add every thing but red so 45+20+32 which equals 97, so 97 is your numerator and to get the denominator you add all the numbers together so 42+45+20+32 which equals 139.
Answer:
Option C.
Step-by-step explanation:
Note : In the given points one point is (8,-2) instead of (-6,-2).
The standard form of a circle is
where, (h,k) is center of circle and r is radius.
It is given that center of the circle is (-1,-2). So,
...(1)
It is given that the circle passing through the point (8,-2),(-1,5),(6,-2),(-1,-9).
Substitute x=6 and y=-2 in equation (1).
Substitute 
in equation (1).
Therefore, the correct option is C.
