Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
<span>What is the approximate circumference of the circle? Use π ≈ 3.14. Circle A with radius 18 feet. 21.1 feet 36 feet 56.5 feet 113 feet PLZ help</span>
The correct answer is -78.15 m.
Hope this helped! :)
Answer:
umm 9 gallons i think
Step-by-step explanation:
The ordered pairs that make this equation true is (4, 10)
A linear equation is given by:
y = mx + b;
where y, x are variables, m is the slope of the line and b is the y intercept.
Given the linear equation: y = 10x - 30:
At (1, -12): y = 10(1) - 30 = -20 ≠ -12
At (8, 1): y = 10(8) - 30 = 50 ≠ 1
At (4, 10): y = 10(4) - 30 = 10
At (6, 20): y = 10(6) - 30 = 30 ≠ 20
The ordered pairs that make this equation true is (4, 10)
Find out more at: brainly.com/question/13911928
