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qaws [65]
4 years ago
13

NEEEDDD HELPPP PLEEASEEE MATHHHHHH HATESS MEEE!!!!!!

Mathematics
2 answers:
Vladimir [108]4 years ago
4 0
Im not sure but i think the answer is b

mars1129 [50]4 years ago
3 0
No, the answer is D and I am 100% sure.
You might be interested in
I need to calculate X<br><br> 2^x=200<br><br> Solve for x
antoniya [11.8K]
Remember
log(a^z)=zlog(a)
so

notice that 200=2*2*2*5*5, so x cannot be a whole number

take the log base 10 of both sides

log_{10}(2^x)=log{10}(200)
xlog_{10}(2)=log{10}(200)
divide both sides by log_{10}(2)
x= \frac{log_{10}(200)}{log_{10}(2)}

if we used log_{2} instead of log_{10} we would get
x= log_{2}(200) because log_{a}(a^b)=b
8 0
4 years ago
Use the identity tan(theta) = sin(theta) / cos(theta) to show that tan(???? + ????) = tan(????)+tan(????) / 1−tan(????) tan(????
VMariaS [17]

Answer:

See the proof below.

Step-by-step explanation:

For this case we need to proof the following indentity:

tan(x+y) = \frac{tan (x) + tan(y)}{1- tan(x) tan(y)}

So we need to begin with the definition of tangent, we know that tan (x) =\frac{sin(x)}{cos(x)} and we can do this:

tan (x+y) = \frac{sin (x+y)}{cos(x+y)}   (1)

We also have the following identities:

sin (a+b) = sin (a) cos(b) + sin (b) cos(a)

cos(a+b)= cos(a) cos(b) - sin(a) sin(b)

Now we can apply those identities into equation (1) like this:

tan (x+y) =\frac{sin (x) cos(y) + sin (y) cos(x)}{cos(x) cos(y) - sin(x) sin(y)}   (2)

We can divide numerator and denominator from expression (2) by \frac{1}{cos(x) cos(y)} we got this:

tan (x+y) = \frac{\frac{sin (x) cos(y)}{cos (x) cos(y)} + \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{cos(x) cos(y)}{cos(x) cos(y)} -\frac{sin(x)sin(y)}{cos(x) cos(y)}}

And simplifying we got:

tan (x+y) = \frac{tan(x) + tan(y)}{1-tan(x) tan(y)}

And that complete the proof.

8 0
3 years ago
K = mv / 2 solve for m . HELP PLEASE HURRY!
Aleksandr-060686 [28]

9514 1404 393

Answer:

  m = 2k/v

Step-by-step explanation:

Identify the coefficient of m (v/2) and multiply by its inverse (2/v).

  (2/v)k = (2/v)m(v/2) . . . . multiply both sides of the equation by 2/v

  2k/v = m . . . simplify

  m = 2k/v

3 0
3 years ago
Can someone explain the quadratic formula please?
brilliants [131]

Answer:

While factoring may not always be successful, the Quadratic Formula can always find the solution. The Quadratic Formula uses the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers; they are the "numerical coefficients" of the quadratic equation they've given you to solve.

source from: https://www.purplemath.com/modules/quadform.htm

your welcome!

6 0
3 years ago
Which situation CANNOT be represented by the equation x + 18 = 52
Andrei [34K]

Answer:

D

Step-by-step explanation:

For D, you would have to ADD 52 to 18.

3 0
3 years ago
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