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pochemuha
3 years ago
12

HELP ME PLS!!! Find the y-intercept of the rational function.

Mathematics
1 answer:
amid [387]3 years ago
6 0

Answer:

-2,0

Step-by-step explanation:

the function intercepts the y axis there

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Answer:

 The crossover point for Time​  h = 6545 \ room \ nights

Step-by-step explanation:

From the question we are told that

     The total rooms rented for the year is  z =  50 * 365 = 18250 \ rooms

       Time's  fixed cost is r =  $61,000

     Time's variable  cost is y =$12.5  per room

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       Duffy's Maid Service variable cost is  k  = $18.00 per room

       

The cross over point for Time is mathematically represented as

        h = \frac{r - x}{k- y}

substituting values

      h = \frac{61000 - 25000}{ 18 - 12.5}

      h = 6545 \ room \ nights

     

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What expression is the opposite of (c - d)?
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Given that sectheta = -37/12 what is the value of cottheta for pi/2 < theta< pi?
lys-0071 [83]

Answer:

cotg(\theta) = -\frac{12}{35}

Step-by-step explanation:

The cotangent of theta is:

cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}

For pi/2 < theta< pi

This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.

Secant:

sec(\theta) = \frac{1}{\cos{\theta}}

In this question

sec(\theta) = -\frac{37}{12}

So

-\frac{37}{12} = \frac{1}{\cos{\theta}}

Using cross multiplication

-37\cos{\theta} = 12

37\cos{\theta} = -12

\cos{\theta} = -\frac{12}{37}

Now we apply the following trigonometric identity:

\sin{\theta}^{2} + \cos{\theta}^{2} = 1

\sin{\theta}^{2} + (-\frac{12}{37})^{2} = 1

\sin{\theta}^{2} = 1 - (-\frac{12}{37})^{2}

\sin{\theta}^{2} = 1 - \frac{144}{1369}

\sin{\theta}^{2} = \frac{1369 - 144}{1369}

\sin{\theta} = \pm \sqrt{\frac{1225}{1369}}

Since the angle is in the second quadrant, the sine is positive.

\sin{\theta} = \frac{35}{37}

Finally, the cotangent:

cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}

cotg(\theta) = \frac{-\frac{12}{37}}{\frac{35}{37}}

cotg(\theta) = -\frac{12}{35}

4 0
4 years ago
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