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ziro4ka [17]
3 years ago
7

*please show work*

Mathematics
1 answer:
Ronch [10]3 years ago
5 0
1.-46
2.-1
3.0
4.60
5.-168
6.4
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PLEASE IM BEGGING ILL GIVE YOU BRAINIEST:
goldenfox [79]

Answer:

32%

Step-by-step explanation:

3 girls like biology, 8 like chem and the rest prefer physics. 28 people like chemistry, and 24 boys like physics. This leaves 29 boys and 3 girls liking bio.

8 0
3 years ago
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60 inches = ______ feet ?<br><br> Please do a step-by-step explanation (no multiple choice)
Firdavs [7]

60 inches = ____ feet ?

60 inches=5 feet

6 0
2 years ago
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The drama club at Central sells hot chocolate and coffee at the high school football games. At the last game, they had sales of
xxTIMURxx [149]

Answer:

I could be wrong but the coffee is 200 and the hot choclet is 266.666666667

Step-by-step explanation:

I used math and a calculator.

3 0
3 years ago
Solve for x: 12x-20=6(x-20)-9x
tigry1 [53]

Answer:

Step-by-step explanation:

12x-20=6(x-20)-9x

Opening bracket

12x - 20 = 6x - 120 - 9x

Collecting like terms

12x - 6x + 9x = -120 + 20

15x = -100

Dividing by 15

15x/15 = -100/15

x = -20/3

x = - 6 2/3

6 0
3 years ago
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Sat scores. sat scores of students at an ivy league college are distributed with a standard deviation of 250 points. two statist
erik [133]

The confidence interval for confidence level of 1-\alpha is

\left(\overline x-Z_{\alpha/2}\dfrac\sigma{\sqrt n},\overline x+Z_{\alpha/2}\dfrac\sigma{\sqrt n}\right)

where \overline x is the sample mean, Z_{\alpha/2} is the critical value for the given confidence level, \sigma is the standard deviation of the population, and n is the sample size. The margin of error is the Z_{\alpha/2}\dfrac\sigma{\sqrt n} term.

a) For a confidence level of 1-\alpha=0.90, we have Z_{\alpha/2}=Z_{0.05}\approx1.64. So in order to have a margin of error of at most 25 points, we have

1.64\dfrac{250}{\sqrt n}=25\implies n\approx268.96

so Raina should collect a sample of at least 269 students.

b) A confidence interval with a higher confidence level would more closely approximate and reflect the population, so it stands to reason that Luke should collect a larger sample than Raina to meet his 99% confidence spec.

c) For a confidence level of 1-\alpha=0.99, we have Z_{\alpha/2}=Z_{0.005}\approx2.58. Then the margin of error would at most satisfy

2.58\dfrac{250}{\sqrt n}=25\implies n\approx665.64

so that Luke should collect a sample of at least 666 students.

4 0
3 years ago
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