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omeli [17]
2 years ago
6

Please answer below :-)

Mathematics
1 answer:
Evgen [1.6K]2 years ago
3 0

Answer:

2\frac{7}{10}

Step-by-step explanation:

First, find the LCM and multiply through:

12(\frac{2x-1}{4} ) +12(\frac{x}{3})=12(2)

The LCM will cancel out the denominators (note that braket symbolizes Multiplication):

:3(2x-1) +4(x)=24

:6x-3+4x=24

Group like terms:

6x+4x=24+3

10x=27

Divide through by 10 to eliminate the coefficient of x

\frac{10x}{10}=\frac{27}{10}

: x=\frac{27}{10}=2\frac{7}{10}

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If the price of a textbook is $40 before tax is added on, and tax is 10%, what will the final price of the textbook be?
Digiron [165]

Answer:

soln,

price of textbook = $40

tax% = 10%

now,

tax amount = 10% of $40

= 10\100*40

= 10*4/10

= 40/10

= $4.

again,

final price = cost of textbook+tax

=$40+$4

=$44.

Step-by-step explanation:

so the total price of a Textbook is $40 which is 100% and the tax is 10% so you need to find tax from the price of the textbook which is 10% of the price of the textbook then add the price of the textbook with the tax amount which is the final cost .

4 0
3 years ago
4.
LekaFEV [45]

Answer: C, 7.5

Step-by-step explanation: Since he can ring up 2 customers in 8 minutes, that would mean he can ring up 4 in 16 minutes. He could also ring up 6 in 24 minutes. He could do this since every two customers is 8 minutes. 4 minutes would mean he could do 1 customer and 2 minutes would be .5 customer. So, at 24 minutes he could ring 6 customers and a extra 6 minutes to 30 minutes would add 1.5 customers to a total of 7.5 customers in half an hour (30 minutes)

7 0
3 years ago
PLEASE HELP ASAP !!
wariber [46]

Answer:

     <u>First figure:</u>            954cm^3

     <u>Second figure:</u>      1,508yd^3

     <u>Third figure:</u>

  •          Height= q
  •           Side length = r

     <u>Fourth figure: </u>        726cm^3

Explanation:

<u></u>

<u>A. First figure:</u>

<u>1. Formula:</u>

            \text{Volume of a cylinder}=\pi \times radius^2\times length

<u>2. Data:</u>

  • radius = 9cm / 2 = 4.5cm
  • length = 15 cm

<u>3. Substitute in the formula and compute:</u>

          Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3

<u>B. Second figure</u>

<u>1. Formula: </u>

       \text{Volume of a leaned cylinder}=\pi \times radius^2\times height

<u>2. Data:</u>

  • radius = 12yd
  • height = 40 yd

<u>3. Substitute and compute:</u>

      Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3

<u></u>

<u>C) Third figure</u>

a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u>  </u><u>q  </u>.

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e.<u>  r </u><u> </u>.

When the base of the pyramid is a square the four edges of the base have the same side length.

<u>D) Fourth figure</u>

<u>1. Formula</u>

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

          Volume=(1/3)B\times H

<u>2. Data: </u>

  • height: H = 18cm
  • side length of the base: 11 cm

<u>3. Calculations</u>

a) <u>Calculate the area of the base</u>.

The base is a square of side length equal to 11 cm:

          \text{Area of the base}=B=(11cm)^2=121cm^2

b) <u>Volume of the pyramid</u>:

         Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3

4 0
3 years ago
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Scorpion4ik [409]
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3 years ago
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