Answer:
soln,
price of textbook = $40
tax% = 10%
now,
tax amount = 10% of $40
= 10\100*40
= 10*4/10
= 40/10
= $4.
again,
final price = cost of textbook+tax
=$40+$4
=$44.
Step-by-step explanation:
so the total price of a Textbook is $40 which is 100% and the tax is 10% so you need to find tax from the price of the textbook which is 10% of the price of the textbook then add the price of the textbook with the tax amount which is the final cost .
Answer: C, 7.5
Step-by-step explanation: Since he can ring up 2 customers in 8 minutes, that would mean he can ring up 4 in 16 minutes. He could also ring up 6 in 24 minutes. He could do this since every two customers is 8 minutes. 4 minutes would mean he could do 1 customer and 2 minutes would be .5 customer. So, at 24 minutes he could ring 6 customers and a extra 6 minutes to 30 minutes would add 1.5 customers to a total of 7.5 customers in half an hour (30 minutes)
Answer:
<u>First figure:</u> 
<u>Second figure:</u> 
<u>Third figure:</u>
- Height= q
- Side length = r
<u>Fourth figure: </u> 
Explanation:
<u></u>
<u>A. First figure:</u>
<u>1. Formula:</u>

<u>2. Data:</u>
<u>3. Substitute in the formula and compute:</u>

<u>B. Second figure</u>
<u>1. Formula: </u>

<u>2. Data:</u>
<u>3. Substitute and compute:</u>

<u></u>
<u>C) Third figure</u>
a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u> </u><u>q </u>.
The apex is the point where the three leaned edges intersect each other.
b) The side length is the measure of the edge of the base, i.e.<u> r </u><u> </u>.
When the base of the pyramid is a square the four edges of the base have the same side length.
<u>D) Fourth figure</u>
<u>1. Formula</u>
The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

<u>2. Data: </u>
- side length of the base: 11 cm
<u>3. Calculations</u>
a) <u>Calculate the area of the base</u>.
The base is a square of side length equal to 11 cm:

b) <u>Volume of the pyramid</u>:

3 + (2 + 8)^2 / 4 * (1/2)^4
3 + 10^2 / 4 * (1/2)^4
3 + 100/4 * (1/2)^4
3 + 25 * 1/16
3 + 25/16
48/16 + 25/16
73/16
4 9/16 <==
A’ (0,5) B’ (5,0) C’ (0, -5) D’ (-5,0)