I can't do much graphing on here but the first equation has a vertical asymptote at x = 4. You get this by taking the denominator (x - 4) and setting it equal to zero. The answer x = 4 will be the asymptote.
The second equation will have a vartical asymptote at x = -2.
Again taking the denominator (x + 2) setting it to zero and solve. x = -2 will be the solution ans the asymptote.
Answer:
2x²=6x-5= x=3+i/2
-x²-10x=34= x = -(5+3i)
Step-by-step explanation: 2x²=6x-5 and -x²-10x=34 are the answers
Steps to solve
1) We have 5 +(-8)n = 29, which we can change to 5 - 8n = 29, because a positive times negative equals a negative
2) To isolate n, we move all of the other numbers to the other side of the equation. Since 5 is the only number on the left side, we subtract 5 from both sides
5 -5 - 8n = 29 -5
-8n = 24
3) Now, to find n, we want to just have one n on the left side instead of -8, so we divide the equation by -8 to find that
-8n/-8 = 24/8
n = 3
Therefore, n = 3
Answer:
77
Step-by-step explanation:
3) HK = 2√5
midpoint of HK = (8,8)
4) SR = 2√2
R = (6,2)
5) Instead of walking a total of 14 he only would have walked a total of 10.
Hope this helps! ;)
