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3 years ago

I need help with this paper

Mathematics

2 answers:

viktelen [127]3 years ago

4 0

Answer:

1st one:

37 - 25 = 12

2nd one (to the right of the one on the top-left):

(19 - 10) - 7 = 2

3rd one (below the one of the top-left):

Since BD = 13 and CD = 10, BC must equal 3.

AC would equal the sum of 8 and 3.

8 + 3 = AC

11 = AC

4th one:

Not exactly sure what you want to find here, add more info.

But if you want to find the middle or mid-point:

10 + 3x + 5 = 25

15 + 3x = 25

3x = 10

Divide by 3 on both sides:

x = 3.33 or 31/3 or 10/3

5th one (bottom-left):

*First find x*

9 + x + 2x - 3 = 30

6 + 3x = 30

3x = 24

Divide both sides by 3:

x = 8

*Now that you have x, you can find the length of DE:

2(8) - 3 = DE

16 - 3 = DE

13 = DE

svp [43]3 years ago

3 0

What grade is this?..

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A sequence is defined recursively by the following rules: f(1)=3f(n+1)=2⋅f(n)−1 Which of the following statements is true about

Radda [10]

Answer:

f(2)=5

f(5)=33

Step-by-step explanation:

The given formula, that recursively defines the sequence is

$f(1) = 3 \\ f(n + 1) = 2f(n) - 1$

When n=1, we obtain;

$f(1+ 1) = 2f(1) - 1 \\ f(2) = 2 \times 3 - 1 \\ f(2) = 6 - 1 \\ f(2) = 5$

When n=2, we get:

$f(2+ 1) = 2f(2) - 1 \\ f(3) = 2 \times 5 - 1 \\ f(3) = 10 - 1 \\ f(3) = 9$

When n=3,

$f(3 + 1) = 2f(3) - 1 \\ f(4) = 2f(3) - 1 \\ f(4) = 2 \times 9 - 1 \\ f(4) = 18 - 1 \\ f(4) = 17$

When n=4

$f(4 + 1) = 2 f(4) - 1 \\ f(5) = 2 \times 17 - 1 \\ f(5) = 34 - 1 \\ f(5) = 33$

When n=5,

$f(6) = 65$

4 0

3 years ago

Assigned newbits with the opposite values of oldbits if flipbits is true. ex: if oldbits = [1, 1, 0, 1] and flipbits is 1, then

Kisachek [45]

Franck's answer is better (using ~), but I just wanted to point out that the conditional in yours is slightly redundant. It's easy to forget that, since you already have a boolean value, you don't need to perform a comparison in your conditional. So you could have just done this...

if x x = false; else x = true; end

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3 years ago

What is 5/8 + 3/4 using these sticks

uysha [10]

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