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3 years ago

In research, the researcher ultimately wants to answer a question about...

1 answer:

8 0

In all the research, the researcher ultimately want to answer question about the population. Mostly educational researchers ultimately want the answer to a question pertain to the target population. When we are conducting surveys or research, we need target population to ask question about the research we are conducting. The answer to this question is B.

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Select the symbol that accurately replaces the ? Evaluate | -17 | ? | -16|

Yakvenalex [24]

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absolute 17 would be greater because the absolute signs cancel out the negatives

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3 years ago

Plz help very important

allsm [11]

I hate questions like this. It's like wishing for more wishes.

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3 years ago

HELP ME ASAP WITH THESE MATH PROBLEMS

NARA [144]

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3 years ago

A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa

diamong [38]

Answer:

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Solution to the problem

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}= \mu_D$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C,D$

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p=4$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0

4 years ago

using distance formula what is the distance point between (-8,4) and (-4,-1) round to nearest tenth

RideAnS [48]

Answer:

6.4 units

Step-by-step explanation:

Distance² = (change in y)² + (change in x)²

Distance² = (4 - -1)² + (-8 - -4)²

Distance² = 25 + 16 = 41

Distance = $\sqrt{41}$ = 6.403124237

The distance is 6.4 units (rounded off to nearest tenth)

8 0

4 years ago