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Talja [164]
4 years ago
9

A carton of milk contains 2.5L. If Zoe drinks 250ml twice a day, for how many days will the bottle last? The answer is 5 days bu

t how? Please help
Mathematics
1 answer:
frez [133]4 years ago
3 0
The main thing you need to know for this question is this conversion:

1 L = 1000 mL   ,   or 1 liter is equal to 1000 milliliters.

So, let's make the entire problem into milliliters:
The carton of milk has 2,500 mL, and Zoe drinks 500 mL a day (250 twice a day).

To find the number of days the bottle will last, you divide the total amount of milk by the amount she drinks per day:

2,500 / 500 = 5 days 
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lesya692 [45]

Given that: a = 2, b = -4

\sqrt{a^3-7}\text{ + |b| = }\sqrt{2^3-7}\text{ + |-4| = }\sqrt{8-7}\text{ }+\text{ 4 = }\sqrt{1}+\text{ 4 = 1 + 4 = 5}

3 0
1 year ago
Which points are separated by distance of 6 units?
MAVERICK [17]
D this because 7 minus 1 is 6
3 0
3 years ago
What are the solutions to the system of circle and line when the circle is given by x²+y²=9, and the line is given by y=4?
san4es73 [151]

Answer:

√7i = x

Step-by-step explanation:

x²+y²=9;

y² = 9-x²

y = √(9-x²)

As line is given by y= 4, the solution of the system is:

4 = √(9-x²)

16 = 9-x²

7 = -x²

-7 = x²

√-7 = x

As √-7 doen't exist, you should use i = √-1;

Thus,

<em>√7i = x</em>

<em></em>

I hope it helps!

4 0
3 years ago
The length of the midsegment of a triangle is always half the length of the side it is parallel to true or false
Vladimir [108]
True. The midsegment of a triangle is halfway up the triangle, and since the top half and the full triangle are similar triangles, its dimensions are proportional.

This means half the height will give half the base (midsegment). So the midsegment is always half the length of the side it's parallel to.
3 0
3 years ago
Darla found that the least common denominator needed to subtract \frac{x}{x^2+4x-12}-\frac{3}{x+6}is (x + 6)(x – 2). Which is th
Leona [35]
<h3>Answer: Choice B</h3>

\frac{x}{(x+6)(x-2)} - \frac{3(x-2)}{(x+6)(x-2)}

which is the same as x/((x+6)(x-2)) - 3(x-2)/((x+6)(x-2))

=====================================

Explanation:

The LCD is (x+6)(x-2) which is the factorization of x^2+4x-12, and that is the denominator of the first fraction. The first fraction has the LCD already. The second fraction does not. It has (x+6) but it is missing (x-2).

We multiply top and bottom of the second fraction by (x-2) to get the second fraction to have the LCD.

\frac{3}{x+6} turns into \frac{3}{x+6}*\frac{x-2}{x-2} = \frac{3(x-2)}{(x+6)(x-2)}

------

So,

\frac{x}{x^2+4x-12} - \frac{3}{x+6}

\frac{x}{(x+6)(x-2)} - \frac{3}{x+6}

\frac{x}{(x+6)(x-2)} - \frac{3(x-2)}{(x+6)(x-2)}

This is the same as x/((x+6)(x-2)) - 3(x-2)/((x+6)(x-2))

Note the parenthesis around "(x+6)(x-2)"

Instead of x/(x+6)(x-2) you should write x/( (x+6)(x-2) ) to ensure that all of "(x+6)(x-2)" is in the denominator.

4 0
3 years ago
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