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4 years ago

What is the volume of a cube with a side length of 3t exponet of 5units?

Mathematics

2 answers:

Fudgin [204]4 years ago

8 0

Answer: 27t^15 units 3

Step-by-step explanation:

i did the assingment

bulgar [2K]4 years ago

5 0

Answer:

C 27t exponent of 15 units cubed

Step-by-step explanation:

V = s³

s = 3t⁵

V = (3t⁵)³

V = 3³ × (t⁵)³

V = 27 × t¹⁵

V = 27t¹⁵

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

vaieri [72.5K]

x²(x - 4)(2x + 5) = 0

x² = 0 or x - 4 = 0 or 2x + 5 = 0

√x = √0 or x = 4 or 2x = -5

x = 0 x = $-\frac{5}{2}$

Answer: 0, 4, $-\frac{5}{2}$

8 0

4 years ago

Look for a pattern in the data set to determine which kind of model best describes the data.

yawa3891 [41]

If you graph it, it looks linear.

4 0

3 years ago

The surface area of an oil spill gets 131% larger every day, represented by the function s(x) = (1.31)x − 1. On the first day, i

scoray [572]

Answer:

The correct option is B.

Step-by-step explanation:

It is given that the surface area of an oil spill gets 131% larger every day, represented by the function

Where x is number of days.

On the first day, it covered an area of 21 square meters. It means the initial area is 21 square meters.

The function is defined as

Where is initial value and b is growth factor.

It means the function of new area is the product of initial area and increasing area function. The required function is

Therefore option B is correct.

6 0

3 years ago

H(x) = ax^2 +1<br> Find the value of a when h(-2) = 21.

blagie [28]

Answer:

$a = 5$

Step-by-step explanation:

Solving $h(-2) = 21$ :

$h(-2) = 21 \\ a(-2)^2 +1 = 21 \\ a(4) +1 = 21 \\ 4a +1 = 21 \\ 4a +1 -1 = 21 -1 \\ 4a = 20 \\ \frac{4a}{4} = \frac{20}{4} \\ a = 5$

4 0

3 years ago

If tan (theta) =5/4 and cos (theta) < 0 . Find the other trig. functions.

andrew-mc [135]

Tan(theta) = 5/4
sin(theta)/cos (theta)=5/4
cos(theta)=4sin(theta)/5
sin²(theta)+cos²(theta)=1
sin²(theta)+16sin²(iheta)/25=1 /*25
25 sin²(theta)+16 sin²(theta)=25
sin²(theta)=25/41 /√
sin(theta)= $\frac{-5 \sqrt{41} }{41}$
cos(theta)= $\frac{-4 \sqrt{41} }{41}$
cot(theta)= $\frac{4}{5}$
csc(theta)=1/sin(theta)= $\frac{- \sqrt{41} }{5}$
sec(theta)=1/cos(theta)= $\frac{- \sqrt{41} }{4}$

5 0

3 years ago