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lara31 [8.8K]
3 years ago
13

Consider the line y= -(5/3)x+2.

Mathematics
1 answer:
klasskru [66]3 years ago
6 0
1. Perpendicular means that the slope is the negative reciprocal.
Negative reciprocal of -5/3=3/5

Use point slope form.
y-3=3/5(x-6)
y-3=3/5x-18/5
y=3/5x-3/5

2. Parallel means that the slope is the exact same.

Use point slope form.
y-3=-5/3(x-6)
y-3=-5/3x+10
y=-5/3x+13

Hope this helps!
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Which is the side length of a cube with a volume of 2744 cm3?<br><br> Please help
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\sf2744=a^3

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Which equation represents a circle that contains the point (-5, -3) and has a center at (-2, 1)?
oksian1 [2.3K]

Answer:

(x+1)2+(y−2)2=5

Explanation:

The general form for a circle with center  

(a,b) and radius r is XXX(x−a)2+(y−b)2=r2

With center  (−1,2) and given that  (0,0) is a solution (i.e. a point on the circle),according to the Pythagorean Theorem: XXX r 2=(−1−0)2+(2−0)2=5

and since the center is  (a,b)=(−1,2)by applying the general formula we get:XXX(x+1)+(y−2)2=5

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its already in the answer

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Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m
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Answer:

1. 0.0000454

2. 0.01034

3. 0.0821

4. 0.918

Step-by-step explanation:

Let X be the random variable denoting the number of passengers arriving in a minute. Since the mean arrival rate is given to be 10,  

X \sim Poi(\lambda = 10)

1. Requires us to compute

P(X = 0) = e^{-10} \frac{10^0}{0!} = 0.0000454

2.  We need to compute P(X \leq 3) = P(X =0) + P(X =1) + P(X =2) + P(X =3)

P(X =1) = e^{-10} \frac{10^1}{1!} = 0.000454

P(X =2) = e^{-10} \frac{10^2}{2!} = 0.00227

P(X =3) = e^{-10} \frac{10^3}{3!} = 0.00757

P(X \leq 3) =0.0000454+ 0.000454 + 0.00227 + 0.00757 = 0.01034

3. The expected no. of arrivals in a 15 second period is = 10 \times \frac{1}{4} = 2.5. So if Y be the random variable denoting number of passengers arriving in 15 seconds,

Y \sim Poi(2.5)

P(Y=0) = e^{-2.5} \frac{2.5^0}{0!} = 0.0821

4. Here we use the fact that Y can take values 0,1, \dotsc. So, the event that "Y is either 0 or \geq 1" is a sure event ( i.e it has probability 1 ).

P(Y=0) + P(Y \geq 1) = 1 \implies P(Y \geq 1) = 1 -P(Y=0) = 1 - 0.0821 = 0.918

3 0
3 years ago
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