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____ [38]
3 years ago
9

Answer ASAP!!!!!!!!!!! 20 POINTS

Mathematics
2 answers:
kondor19780726 [428]3 years ago
7 0

Answer:56

Step-by-step explanation:

igor_vitrenko [27]3 years ago
6 0
I think i had this question on my math quiz, i got 56?
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Which of the following is equivalent to 5/13^3
lys-0071 [83]

Answer:

.00227 or 5/2197

Step-by-step explanation:

following the basic rules of PEMDAS, we know that we have to solve for the exponent first.

so.... 5/2197

as a decimal, this is .00227...

8 0
4 years ago
A bag with 8 marbles are shown below.What is the probability that they are white or grey
horrorfan [7]

Answer: 2/8

Step-by-step explanation:

The probability that the marbles are white or grey is 2/8 because since there is 2 marbles and the total is 8 so you have a probability of 25% to get white or gray

3 0
3 years ago
8
const2013 [10]
35 x 0.14 = 4.9

The total tip would be $4.9
3 0
3 years ago
Read 2 more answers
6 = -5 -x solve for x
makkiz [27]

Answer:

<h2>x = -11</h2>

Step-by-step explanation:

In algebra, the goal is always to isolate the variable, so that its value can be determined.

<h3>Step 1: Add x</h3>

6 + x = -5

<h3>Step 2: Subtract 6</h3>

x = -11

<h3>Step 3: Check</h3>

6 = -5 - -11

6 = -5 + 11

6 = 6 ✔

<h3>Step 4: Answer</h3>

x = -11

I'm always happy to help :)

7 0
3 years ago
A furniture designer builds a trapezoidal desk with a semicircular cutout. What is the area of the desk?
nirvana33 [79]

Answer:

Area = 26478cm^2

Step-by-step explanation:

Given

See attachment for desk

Required

The area

First, calculate the area of the semicircular cutout

Area = \frac{\pi r^2}{2}

Where

r = 60cm

So:

A_1 = \frac{3.14 * 60^2}{2}

A_1 = \frac{11304}{2}

A_1 = 5652cm^2

Next, the area of the complete trapezium

Area= \frac{1}{2}(a + b) * h

Where

a = 300

b = 2 * r = 2 * 60 = 120

h = 153

So:

A_2 = \frac{1}{2} * (300 + 120) * 153

A_2 = \frac{1}{2} * 420 * 153

A_2 = 32130cm^2

The area of the desk is:

Area = A_2 - A_1

Area = 32130cm^2 - 5652cm^2

Area = 26478cm^2

8 0
3 years ago
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